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DIA [1.3K]
3 years ago
9

state position nature and size of an image when an object placed at an distance equal to its focal length of rear view in vehicl

es​
Physics
1 answer:
maksim [4K]3 years ago
5 0

Answer:

The position nature and size of an image when an object placed at a distance equal to its focal length of rear view mirrors in vehicle will be

1) Position: Behind the mirror

2) Nature: Virtual

3) Size: Smaller than the object

Explanation:

Due to the nature and use of rear view mirrors, which are meant to enable the front facing driver visualize a wide area of the back portion of the vehicle, such that the images of the object will always remain smaller than the object, require a convex image

The image size, location, nature and orientation of an object placed in front of a convex mirror is diminished, behind the mirror of the upright, virtual, and upright

Therefore, the position nature and size of an image when an object placed at a distance equal to its focal length of rear view mirrors in vehicle will be

Position: Behind the mirror

Nature: Virtual

Size: Smaller than the object.

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Monica [59]

Answer:

1. The reason why nichrome wire is used in a heater is due to the properties of nichrome which makes it a material of choice for heating application including;

i) The cost of manufacture of nichrome is low

ii) Nichrome has both high mechanical and creep strength, and therefore is suitable for installation and use in a wide setting

iii) Nichrome has a high resistance to electron flow, making it a good electrical heating element

iv) Nichrome has a high resistance to oxidation, such that it can be reused several times as a heater

v) The high ductility of nichrome allows it to be stretched and drawn around different vessels with contents to which heat is to be supplied

2. Copper wire is not used in heaters because according to Joule's law, the heat produced from the flow of electric current, 'I', through a material having a resistance, 'R', for a time, 't', is proportional to I²·R·t, and copper has a very low resistance, 'R', to the flow of electric current, and therefore, will not produce sufficient heat required at a given current level

Explanation:

3 0
3 years ago
Iron filings scattered around a magnet will be most strongly drawn toward the _____.
victus00 [196]
<span>The answer is towards <span>the poles. This is because, at the poles of the magnet, the magnetic field lines get closer together hence indicating that the magnetic force is stronger here. The fields are closest together at the center of the magnet and farthest at the outside side of the magnet. </span></span>




8 0
3 years ago
Read 2 more answers
How is energy involved in the formation of a covalent bond?
frez [133]

The energy is involved in ionization, electron affinity etc

The following are the conditions that favor the creation of covalent bonds since they are generated by the mutual sharing of electrons:

  • Electron affinity, first. If both atoms have a strong electron affinity, a covalent link is often preferred between them.
  • The energy of ionization. The ionization energy of the two atoms participating in the bonding process should be high.
  • Atomic Dimension. The atoms that form covalent bonds should have lower atomic sizes. Stronger covalent bonds are created when atoms have smaller atomic radii.
  • Electronegativity. Both atoms' electronegativities ought to be high. The two atoms' electronegativities should differ as little as possible.
  • In order to establish covalent bonds, the atoms' high ionization energy is involved.

To learn more about covalent bond visit:

brainly.com/question/19382448

#SPJ9

5 0
1 year ago
Could somebody double check my work???
irina1246 [14]

Answer:

I think it's correct. Hope it helps.

5 0
3 years ago
A 2 000-kg sailboat experiences an eastward force of 3 000 N by the ocean tide and a wind force against its sails with a magnitu
Vesnalui [34]

Answer:

The magnitude of the resultant acceleration is 2.2 m/s^2

Explanation:

Mass (m) of the sailboat =  2000 kg

Force acting on the sailboat due to ocean  tide is F_1 = 3000N

Eastwards means takes place along the positive x direction

ThenF_{1x} = 3000N and F_{1y}= 0

Wind Force acting on the Sailboat isF_2  = 6000N directed towards the northwest that means at an angle  45 degree above the negative x axis

Then  

F_{2x} = -(6000N) cos 45 degree = -4242.6 N

F_{2y}  = (6000N) cos 45 degree = 4242.6 N

Hence  , the net force acting on the sailboat in x direction is  

F_x = F_{1x}+ F_{2x}

=  - 3000 N + 4242.6 N

=  - 3000 N +4242.6 N

= 1242.6N

Net Force acting on the sailboat in y direction is  

F_y = F_{1y}+ F_{2y}

= 0+ 4242.6N

= 4242.6N

The magnitude of the resultant force =

Using pythagorean theorm of 1243 N and 4243 N

\sqrt{(1242.6)^2 + (4242.6)^2

\sqrt{(1544054.76) + (17999654.8)}

\sqrt{(19543709.5)^2}

4420.8 N

F = ma

a = \frac{F}{m}

a =\frac{4420.8}{ 2000}

=2.2 m/s^2

4 0
4 years ago
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