Explanation:
gas vibrate and moves freely at high speeds, liquid vibrate, move about, and slide past each other. solid vibrate (jiggle) but generally do not move from place to place
hope it helps you
Answer:
Explanation:
Given
Mass of ice 
mass of water 
Initial Temperature of water 
Let T be the Final Temperature of mixture
Latent heat of Fusion 
heat required to melt ice completely is

Heat released by water is taken by ice thus



1) Focal length
We can find the focal length of the mirror by using the mirror equation:

(1)
where
f is the focal length

is the distance of the object from the mirror

is the distance of the image from the mirror
In this case,

, while

(the distance of the image should be taken as negative, because the image is to the right (behind) of the mirror, so it is virtual). If we use these data inside (1), we find the focal length of the mirror:

from which we find

2) The mirror is convex: in fact, for the sign convention, a concave mirror has positive focal length while a convex mirror has negative focal length. In this case, the focal length is negative, so the mirror is convex.
3) The image is virtual, because it is behind the mirror and in fact we have taken its distance from the mirror as negative.
4) The radius of curvature of a mirror is twice its focal length, so for the mirror in our problem the radius of curvature is:
Answer:
ΔP = (640 N/cm^2)
Explanation:
Given:-
- The volume increase, ΔV/V0 = 4 ✕ 10^-3
- The Bulk Modulus, B = 1.6*10^9 N/m^2
Find:-
Calculate the force exerted by the moonshine per square centimeter
Solution:-
- The bulk modulus B of a material is dependent on change in pressure or Force per unit area and change in volume by the following relationship.
B = ΔP / [(ΔV/V)]
- Now rearrange the above relation and solve for ΔP or force per unit area.
ΔP = B* [(ΔV/V)]
- Plug in the values:
ΔP = (1.6*10^9)*(4 ✕ 10^-3)
ΔP = 6400000 N/m^2
- For unit conversion from N/m^2 to N/cm^2 we have:
ΔP = (6400000 N/m^2) cm^2 / (100)^2 m^2
ΔP = (640 N/cm^2)
No. You cannot rule out the battery even after the open circuit voltage measurement. The open-circuit voltage may not have changed but the battery's internal resistance may have greatly increased.