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Aneli [31]
3 years ago
14

If an otherwise empty pressure cooker is filled with air of room temperature and then placed on a hot stove, what would be the m

agnitude of the net force f120 on the lid when the air inside the cooker had been heated to 120∘c? assume that the temperature of the air outside the pressure cooker is 20∘c (room temperature) and that the area of the pressure cooker lid is
a. take atmospheric pressure to be pa. treat the air, both inside and outside the pressure cooker, as an ideal gas obeying pv=nkbt.
Physics
1 answer:
Margaret [11]3 years ago
6 0

Ideal Gas Law is, pV = NkbT

<span>Therefore, p/t  = Nkb/V which is equal to the constant</span>

We need to convert the given temperature to Kelvin. We need to add 273 to have the Kelvin of the temperature from Celsius.

T1= 20 + 273 = 293 K

T2= 120 + 273 = 393 K

With this we have the pressure ration of 393/293.

So,F120 = 1.34 APa

<span> </span>

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<span>Scientists follow a set order of steps when carrying out a scientific investigation to make sure that the method, interpretation and results that they have obtained are repeatable and reliable. This kind of information can be truly said that their data is true and valid. </span>
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3 years ago
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A hockey puck slides 55.0 m along the length of the rink in just 1.25 s. The slight friction between the puck and the ice provid
topjm [15]

Answer:

44.8 m/s

Explanation:

Use the Initial Speed Formula:

InS = 2(d/t) - Final Speed

InS = 2(55/1,25) - 43.2

InS = 2.44 - 43,2

InS = 88 - 43,2

InS = 44.8 m/s

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A building is being knocked down with a wrecking ball, which is a big metal sphere that swings on a 12-m-long cable. You are (un
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Because you know that gravity is in m/s^2 so, period will be measured in seconds. You know the cable is 12m long and gravity is 9.81 solve for T (period) 2π12sqrt(9.81)=6.94922
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3 years ago
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Which combination of these devices monitors waves that have a compressional component?
kompoz [17]

Answer:

The answer is A

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4 0
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Assume that the driver begins to brake the car when the distance to the wall is d=107m, and take the car's mass as m-1400kg, its
Evgen [1.6K]

Answer:

Explanation:

a ) Let let the frictional force needed be F

Work done by frictional force = kinetic energy of car

F x 107 = 1/2 x 1400 x 35²

F = 8014 N

b )

maximum possible static friction

= μ mg

where μ is coefficient of static friction

= .5 x 1400 x 9.8

= 6860 N

c )

work done by friction for μ = .4

= .4 x 1400 x 9.8 x 107

= 587216 J

Initial Kinetic energy

= .5 x 1400 x 35 x 35

= 857500 J

Kinetic energy at the at of collision

= 857500 - 587216

= 270284 J

So , if v be the velocity at the time of collision

1/2 mv² = 270284

v = 19.65 m /s

d ) centripetal force required

= mv₀² / d which will be provided by frictional force

= (1400 x 35 x 35) / 107

= 16028 N

Maximum frictional force possible

= μmg

= .5 x 1400 x 9.8

= 6860 N

So this is not possible.

4 0
3 years ago
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