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serious [3.7K]
3 years ago
8

A car travels 30 kilometers north for 2 hours, then travels 45 kilometers east for 3 hours. The car then drives south for 30 kil

ometers for 1.5 hours, finally travels west for 25 kilometers in 0.5 hours. What is the speed of the car? What is the velocity of the car?
Physics
1 answer:
MrRissso [65]3 years ago
5 0
*Let north and east as positive direction.
1. a = +30 km / 2 hr
a = +15 km/hr

2. a = +45 km / 3 hr
a = +15 km/hr

3. a = -30 km / 1.5 hr
a = -20 km/hr

4. a = -25 km / 0.5 hr
a = -50 km/hr

speed = (15+15+20+50) / 4
= 25 km/hr

velocity:
(horizontal): (+15-50)= -35 km/hr
(vertical): (+15-20)= -5km/hr
v = sqrt(35^2 + 5^2)
v = 35.36 km/hr
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A step-up transformer is connected to a generator that is delivering 197 v and 113 A. The ratio of the turns on the secondary is
alekssr [168]

Complete Question

A step-up transformer is connected to a generator that is delivering 197 v and 113 A. The ratio of the turns on the secondary to the turns on the primary is 600 to 5. What is the voltage across the secondary

Answer:

The voltage is V_s  =  23640  \  V

Explanation:

From the question we are told that

   The  voltage is  V_p  = 197  \ V

    The current is  I  =  113  \  A

   The  number of turn on the secondary is  N_s =  600 \ turns

    The  number of turn on the primary is  N_p =  5 \  turns

Generally from the Transformer Turns ratio equation

    \frac{N_s}{N_p} = \frac{V_s}{V_p}

=>  \frac{ 600}{ 5} = \frac{V_s}{197 }

=>  V_s  =  23640  \  V

7 0
4 years ago
Helpppp plz heeeeeeeeeeeelp
diamong [38]

Answer:that

Explanation:

8 0
3 years ago
When converted to a household measurement, 9 kilograms is approximately equal to a
Evgen [1.6K]

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8lbs

3 0
3 years ago
3. Liquid nitrogen at 90 K, 400 kPa flows into a probe used in a cryogenic survey. In the return line the nitrogen is then at 16
devlian [24]

Answer:

Specific heat transfer = 236.16 kJ/kg

Ratio of return velocity to inlet velocity = 0.80

Explanation:

Given

Temperature of liquid nitrogen, T1 = 90 K

Pressure of liquid nitrogen, P1 = 400 kPa

Temperature of nitrogen, T2 = 160 K

Pressure of nitrogen, T2 = 400 kPa

A(e) = 100 A(i)

To solve, we use the formula

h(i)+ 1/2v(i)² + q = h(e) + 1/2v(e)² + q

The mass flow is

m = m(i) = m(e)

m = (Av/V)i = (Av/V)e

Ratio of return velocity to inlet velocity is

v(e) / v(i) = A(i)/A(e) * V(e)/V(i)

v(e) / v(i) = 1/100 * V(e)/V(i)

From the saturated Nitrogen table, at 100 K, we have

h(i) = h(f) = -73.2

v(i) = v(f) = 0.001452

From the saturated Nitrogen table again, at 160 K and 400 kPa

h(e) = 162.96 kJ/kg

v(e) = 0.11647 m³/kg

Substituting these in the formula, we have

v(e) / v(i) = 1/100 * 0.11647/0.001452

v(e) / v(i) = 1/100 * 80.2

v(e) / v(i) = 0.80

Energy equation is given by

q + h(i) = h(e)

q = h(e) - h(i)

Now, calculating specific heat transfer

q = 162.96 - -73.2

q = 236.16 kJ/kg

6 0
3 years ago
A police car is driving down the street with it's siren on. You are standing still on the sidewalk beside the street. If the fre
diamong [38]

Answer:

A) 1568.60 Hz

Explanation:

This change is frequency happens due to doppler effect

The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source

f_(observed)=\frac{(c+-V_r)}{(C+-V_s)} *f_(emmited)\\

where

C = the propagation speed of waves in the medium;

Vr= is the speed of the receiver relative to the medium,(added to C, if the receiver is moving towards the source, subtracted if the receiver is moving away from the source;

Vs= the speed of the source relative to the medium, added to C, if the source is moving away from the receiver, subtracted if the source is moving towards the receiver.

A) Here the Source is moving towards the receiver(C-Vs)

and the receiver is standing still (Vr=0) therefore the observed frequency should get higher

f_(observed)=\frac{C}{C-V_s} *f_(emmited)\\=\frac{343}{343-15}*1500\\ =1568.60 Hz

6 0
3 years ago
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