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Kobotan [32]
3 years ago
12

A flower pot falling 45 meters hits the ground with a speed of _________.a. about 60 m/s. b. about 120 m/s. c. more than 120 m/s

. d. about 30 m/s.
Physics
1 answer:
ratelena [41]3 years ago
5 0

Answer:

d. about 30 m/s.

Explanation:

we use the equation for final speed in free fall:

v_{f}^2=v_{0}^2+2gh

where v_{f} is the final speed, v_{0} the initial speed, in this case v_{0}=0, g is the acceleration of gravity g=9.8m/s^2 and h is the height: h=45m

so replacing all known values:

we use the equation for final speed in free fall:

v_{f}^2=0^2+2(9.8m/s^2)(45m)

v_{f}^2=882m^2/s^2

v_{f}=\sqrt{882m^2/s^2} \\v_{f}=29.7m/s

so the answer is:  d. about 30 m/s.

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A concrete block is hung from an ideal spring that has a force constant of 100 N/m . The spring stretches 0.129 m .A- What is th
madam [21]

Answer:

1.31498 kg

0.72050 s

0.72050 s

Explanation:

m = Mass of block

g = Acceleration due to gravity = 9.81 m/s²

k = Spring constant = 100 N/M

x = Displacement = 0.129 m

The force balance is

mg=kx\\\Rightarrow m=\dfrac{kx}{g}\\\Rightarrow m=\dfrac{100\times 0.129}{9.81}\\\Rightarrow m=1.31498\ kg

The mass of the block is 1.31498 kg

Time period is given by

T=2\pi\sqrt{\dfrac{m}{k}}\\\Rightarrow T=2\pi\sqrt{\dfrac{1.31498}{100}}\\\Rightarrow T=0.72050\ s

The period of oscillations is 0.72050 s

The time period does not depend on the acceleration due to gravity. It varies with the mass and the spring constant.

Hence, the time period would be the same

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3 years ago
Please answer of this question​
Bogdan [553]

Answer:

\frac{\pi }{15}m

Explanation:

At 10am, the minute hand and hour hand are ' 2 hours apart', since the minute hand is at 12pm and hour hand is at 10am.

Angle between the two hands = 2/12 * 360

= 60°

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In component form, the displacement vectors become

• 350 m [S]   ==>   (0, -350) m

• 400 m [E 20° N]   ==>   (400 cos(20°), 400 sin(20°)) m

(which I interpret to mean 20° north of east]

• 550 m [N 10° W]   ==>   (550 cos(100°), 550 sin(100°)) m

Then the student's total displacement is the sum of these:

(0 + 400 cos(20°) + 550 cos(100°), -350 + 400 sin(20°) + 550 sin(100°)) m

≈ (280.371, 328.452) m

which leaves the student a distance of about 431.8 m from their starting point in a direction of around arctan(328.452/280.371) ≈ 50° from the horizontal, i.e. approximately 431.8 m [E 50° N].

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Select the correct answer.
elixir [45]

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Such reactions are called endothermic reactions.

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