Answer:
The seed as a fraction of the speed of light is 
Solution:
As per the question:
Suppose, 
be the rate of an identical clock between two time intervals.
For a moving clock, moving with velocity 'v', at the clock tick of four-fifth:
t = 
Now,
Using the relation of time dilation, from Einstein's relation:
Squaring both sides:
The force ffrom the ground that holds the rock up and prevents her from falling through the gound, unless the ground breaks.
Answer:
Magnetic field, B = 0.199 T
Explanation:
It is given that,
Radius of circular loop, r = 11.7 cm = 0.117 m
Magnetic flux through the loop, 
The magnetic flux linked through the loop is :
Here, 
or
B = 0.199 T
So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.
Answer:
The displacement of the car after 6s is 43.2 m
Explanation:
Given;
velocity of the car, v = 12 m/s
acceleration of the car, a = -1.6 m/s² (backward acceleration)
time of motion, t = 6 s
The displacement of the car after 6s is given by the following kinematic equation;
d = ut + ¹/₂at²
d = (12 x 6) + ¹/₂(-1.6)(6)²
d = 72 - 28.8
d = 43.2 m
Therefore, the displacement of the car after 6s is 43.2 m
<span>B. Energy is never created nor destroyed.
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