All categories

2 years ago

Answer pls will give 20 points per person

Physics

2 answers:

LuckyWell [14K]2 years ago

7 0

Answer: question 1 is b I believe

Explanation:

every action has an opposite reaction

pogonyaev2 years ago

5 0

Answer:

Mscalculator is right it is "B" i took it on edge

You might be interested in

Julie wants to know if adding calcium fertilizer to tomato plants will help prevent a disease of tomato plants called blossom-en

Ksivusya [100]

It's not true.

The crucial principle for a scientific experiment is to keep only ONE variable at a time.

In this case, the variable of this experiment is actually the tomato is in sunny part or in shady part, instead of whether applying Ca fertilizer.

3 0

2 years ago

Alright eksqijakojqnlqozjzbw.wlisj

saw5 [17]

Answer:

eksqijakojqnozjzbw.wlisjaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

Explanation:

6 0

2 years ago

6 latter word and it has a s and a I and it has mass (9.______________liquids, and gases all have mass.)

Firdavs [7]

Answer:

Solids

Explanation:

Solids, liquids, and gases all have mass.

7 0

2 years ago

The nuclei of large atoms, such as uranium, with 9292 protons, can be modeled as spherically symmetric spheres of charge. The ra

Scrat [10]

Answer:

Part 1 $E = 2.42 * 10^{21} N/C$

Part 2 $E = 1.3 * 10^{13} N/C$

Part 3 $E = 0$

Explanation:

Given

Number of protons $= 92$

Radius of nucleus $r_n = 7.4 * 10^{-15} m$

Distance of the electrons $r_1 = 1.0 * 10^ {-10} m$

Part 1

Electric field produced by just outside its surface

$E = \frac{q}{4\pi*E_0* r_n^2 } \\E = \frac{9 * 10^ 9 * 92 * 1.6 * 10^{-19}}{(7.4* 10^{-15})^2} \\E = 2.42 * 10^{21} N/C$

Part 2

Electric field produced by just outside its surface

$E = \frac{q}{4\pi*E_0* r_n^2 } \\E = \frac{9 * 10^ 9 * 92 * 1.6 * 10^{-19}}{(1* 10^{-15})^2} \\E = 1.3 * 10^{13} N/C$

Part 3

The net electric field inside a uniform shell of negative charge is zero because the electric flux lines cancel out each other

hence, the solution is

Part 1 $E = 2.42 * 10^{21} N/C$

Part 2 $E = 1.3 * 10^{13} N/C$

Part 3 $E = 0$

7 0

2 years ago

how much does a bookshelf weigh if the movers are pushing it at a speed of 10 m/s^2 by applying 100 N force

Delicious77 [7]

Answer:

10 kg

Explanation:

Assuming a frictionless surface, then force F=ma where F is the applied force, m is the mass and a is acceleration. Making m the subject of the formula then $m=\frac {F}{a}$

Substituting 100 N for the applied force F and 10 m/s^2 for acceleration a then the value of m will be $m=\frac {100}{10}=10\ kgs$

Therefore, in terms of kilograms, the bookshelf weighs 10 Kg

7 0

2 years ago