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2 years ago

Simplify (6 1/4)4 plz help

Mathematics

2 answers:

Ostrovityanka [42]2 years ago

6 0

(6 + 1/4)·4 = (6·4) + (1/4·4) = 24 + 1 = 25

Or, you can convert the mixed number to the improper fraction 25/4 and then multiply by 4 to get 25.

PolarNik [594]2 years ago

4 0

Answer:6

Step-by-step explanation:

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grigory [225]

We’ll first find how much she has left as her savings
$490-$396.90= $93.70

Now we’ll go for cross multiplication
100% $490
? $93.70

? = 100 x 93.7/490
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So the answer is 19.1% which rounded to the nearest whole number is 19%. The answer is the first option.
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8 0

2 years ago

Find the area of the shaded region. The radius of the large circle is 10 m. Round answer to the nearest hundredth.

vivado [14]

Answer:

hello the figure related to your question is missing attached below is the missing figure

answer : 157.08 m^2

Step-by-step explanation:

Calculate the area of the shaded area

= Area of the large circle - Areas of the small circles

= (( $\frac{\pi }{4}$ ) * D^2) - 2( ( $\frac{\pi }{4}$ ) * d^2 ) given that the small circles are congruent

= (( $\frac{\pi }{4}$ ) * 20^2 ) - 2 ( ( $\frac{\pi }{4}$ ) * 10^2 )

= 314.16 - 157.08

= 157.08 m^2

8 0

2 years ago

From 1995-2005, the hourly pay for lifeguards at an outdoor swimming pool increased by 2% per year. The hourly pay, P(t), in dol

12345 [234]

Answer:

The hourly pay for the lifeguards in 2001 was of $6.31.

Step-by-step explanation:

The hourly pay, in dollars, in t years after 1995, is given by the following equation:

$P(t) = 5.60(1.02)^{t}$

What was the hourly pay for the lifeguards in 2,001?

2001 is 2001 - 1995 = 6 years after 1995. So this is P(6).

$P(t) = 5.60(1.02)^{t}$

$P(6) = 5.60(1.02)^{6} = 6.31$

The hourly pay for the lifeguards in 2001 was of $6.31.

7 0

2 years ago

two points are given (-1,-4) and (-3,6) use the coordinates of the two points to set up the equation for rate of change the solv

lisabon 2012 [21]

The formula to find the rate of change is y2-y1/x2-x1
6-(-4)/-3-(-1)
=10/-2
=-5

4 0

3 years ago

Write the interval (5,100] as an inequality and using set notation

drek231 [11]

Answer: { x | 5 < x ≤ 100 } OR { x ∈ ℝ | 5 < x ≤ 100 }

Step-by-step explanation:

{ x | 5 < x ≤ 100 }

This means:

"The set of all x's, such that x is greater than 5 and less than or equal to 100"

Another acceptable way to write this is

{ x ∈ ℝ | 5 < x ≤ 100 }

"x ∈ ℝ" simply means x is an element of all real numbers

7 0

2 years ago