Answer: (c) y<=-x+4
The area is shaded UNDER the boundary line, hence "<"
The boundary is plotted as solid line, hence "="
<span>arccos (cos pi/2)=?
</span>cos pi/2=0, arccos (0)=?, we know that cos pi/2=0, so cos^-1 (o)= Pi/2, but cos^-1 (o)=arccos (0), so arccos (cos pi/2)=Pi/2
13 2/3
Hope this helped :)
