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Scorpion4ik [409]
3 years ago
9

Of the pets in the pet show, 5/6 are cats. 4/5 of the cats are calico cats. What fraction of the pets are calico cats?

Mathematics
2 answers:
kondaur [170]3 years ago
4 0

Answer:

8=135.2

Step-by-step explanation:

if it help u can follow me

aliya0001 [1]3 years ago
3 0

Answer:8=135.2

Step-by-step explanation:

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Arthur Jackson can run 1,500 meters in about 3 1/2 minutes. How many meters per minute is this?
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(1500 meters) / (about 3.5 minutes) =

(1500/about 3.5) (meters/minute) =

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an online movie streaming plan has no annual fee but charges $4.25 per movie watched. Another plan charges an annual fee of $36
Juli2301 [7.4K]
X is the number of movies for the cost of the plan to be the same.

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3 0
3 years ago
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A company manufactures televisions. The average weight of the televisions is 5 pounds with a standard deviation of 0.1 pound. As
Semenov [28]

Answer:

0.2564\text{ pounds}

Step-by-step explanation:

The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.

To find the X percentile for the television weights, use the formula:

X=\mu +k\sigma, where \mu is the average of the set, k is some constant relevant to the percentile you're finding, and \sigma is one standard deviation.

As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute \mu=5, k=1.282, and \sigma=0.1:

X=5+(1.282)(0.1)=5.1282

Therefore, the 90th percentile weight is 5.1282 pounds.

Repeat the process for calculating the 10th percentile weight:

X=5+(-1.282)(0.1)=4.8718

The difference between these two weights is 5.1282-4.8718=\boxed{0.2564\text{ pounds}}.

8 0
2 years ago
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2 years ago
What does the solution (8, 5.5) mean in the context of this problem? The cost of 8 child tickets is $5.50. The cost of 8 adult t
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I pretty sure it is D if you give me a thanks I would really appreciate it
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