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3 years ago

Find the vertex of the function given below. Y= x^2-4x+1

Mathematics

2 answers:

deff fn [24]3 years ago

8 0

Answer:

(-1,-1)

Step-by-step explanation:

Nevermined i just noticed the negative sign

Brut [27]3 years ago

7 0

Answer:

The vertex of this function is (2;-3).

Hope this helps!

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Maksim231197 [3]

Based on the given values above, we can find the exchange rate by simply multiplying $100 by the given exchange rate figure of 900.50. And the answer for this one would be 90,050. Therefore, the rate that he would receive is 90,050. It is the third option. Hope this answers your question. Have a great day!

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3 years ago

Given the equation y=23x,whats the value of x if y=100

Damm [24]

Answer: 4.3478 or 100/23

Step-by-step explanation:

Set the y values equal to each other since they are the same unknown (x). You end up with 100=23x, solve for x. Move the 23 over to the other side by using division. x=100/23. If you need it in decimal form, 100÷23=4.347826087

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3 years ago

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Select the tables that show a proportional relationship between x and

forsale [732]

Answer:

213`334

Step-by-step explanation:

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3 years ago

Which sentence does not belong with the other 3?

attashe74 [19]

D, there is no division property of equality

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4 years ago

Which equations for the measures of the unknown

MAXImum [283]

Answer: Option B, Option C, Option E

Step-by-step explanation:

The options written correctly, are:

$A)x = cos^{-1}(\frac{a}{c})\\\\B) x = sin^{-1}(\frac{c}{b})\\\\C)x = tan^{-1}(\frac{c}{a})\\\\D) y = sin^{-1}(\frac{a}{c})\\\\ E)y = cos^{-1}(\frac{c}{b})$

For this exercise you need to use the following Inverse Trigonometric Functions:

$1)\ sin^{-1}(x)\\\\2)\ cos^{-1}(x)\\\\3)\ tan^{-1}(x)\\\\$

When you have a Right triangle (a triangle that has an angle that measures 90 degrees) and you know that lenght of two sides, you can use the Inverse Trigonometric Functions to find the measure of an angle $\alpha$ :

$1)\alpha = sin^{-1}(\frac{opposite}{hypotenuse}) \\\\2)\ \alpha =cos^{-1}(\frac{adjacent}{hypotenuse})\\\\3)\ \alpha=tan^{-1}(\frac{opposite}{adjacent})$

Therefore, the conclusion is that the angles "x" and "y" can be found with these equations:

$x=sin^{-1}(\frac{c}{b})\\\\x= cos^{-1}(\frac{a}{b})\\\\x=tan^{-1}(\frac{c}{a})\\\\\\ y=sin^{-1}(\frac{a}{b})\\\\y=cos^{-1}(\frac{c}{b})\\\\y=tan^{-1}(\frac{a}{c})$

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3 years ago

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