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3 years ago

I need help with 9 help if you can

Mathematics

1 answer:

ale4655 [162]3 years ago

5 0

Answer:

Please find attached pdf

Step-by-step explanation:

Download pdf

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A theater technician charges a $200 flat fee and 5% of all profits from ticket sales per show. If the technician made $400.00 on

ella [17]

The profit would be 5% of 400, or $\frac{5}{100}*400=\frac{400}{20}=20$ , that is, $20 for profit! Not much, I suppose...

4 0

3 years ago

Pls answer fast!! order these numbers from least to greatest ^^

zubka84 [21]

Answer:

Least to Greatest: $-\frac{31}{6}, -\sqrt{26}, -5, -\frac{5}{6}$

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3 years ago

Find a positive number for which the sum of it and its reciprocal is the smallest (least) possible. Let x be the number and let

Allisa [31]

Answer:

$S(x) = x + \frac{1}{x}$ --- Objective function

Interval = $\{x:x=1\}$

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

$x + \frac{1}{x}$

Hence, the objective function is:

$S(x) = x + \frac{1}{x}$

To get the the interval, we start by differentiating w.r.t x

Using first principle, this gives:

$S'(x) = 1 - \frac{1}{x^2}$

Equate S'(x) to 0 in order to solve for x

$0 = 1 - \frac{1}{x^2}$

Subtract 1 from both sides

$0 -1 = 1 -1 - \frac{1}{x^2}$

$-1 = - \frac{1}{x^2}$

Multiply both sides by -1

$1 = \frac{1}{x^2}$

Cross Multiply

$x^2 * 1 = 1$

$x^2 = 1$

Take positive square root of both sides because x is positive

$\sqrt{x^2} = \sqrt{1$

$x = 1$

Representing x using interval notation, we have

Interval = $\{x:x=1\}$

To get the smallest sum, we substitute 1 for x in $S(x) = x + \frac{1}{x}$

$S(1) = 1 + \frac{1}{1}$

$S(1) = 1 + 1$

$S(1) = 2$

Hence, the smallest sum is 2

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3 years ago

What is the area of the base. explain, please :)

Ber [7]

Answer:

4,200

Step-by-step explanation:

7 0

3 years ago

Write the domain as an inequality

Pavlova-9 [17]

Answer:

$x\leq 0$

Step-by-step explanation:

The domain is the span of x-values covered by the graph.

From the graph, we can see that the x-values covered by the graph is all values to the left of zero including zero.

Therefore, the domain is all x-values less than or equal to 0:

$x\leq 0$

Further notes:

In interval notation, this is:

$(-\infty,0]$

4 0

3 years ago

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