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NeX [460]
3 years ago
12

Select the correct answer. Which atomic property is different in each isotope of an element? A. number of protons B. number of e

lectrons C. charge D. mass number E. atomic number
Chemistry
2 answers:
eimsori [14]3 years ago
7 0

(D)mass number is different

larisa [96]3 years ago
4 0

Answer:

D. mass number

Explanation:

Isotopes have the same atomic number and different mass number.  

For example, the three isotopes of C are 14C, 13C and 12C.  

All the isotopes of C have the same atomic number which is 6. But 14C, 13C and 12C have mass number 14, 13 and 12 respectively. Atomic number is equal the number of protons which is also equal to the number of electrons.  Mass number is equal to the sum of the number of protons and neutrons.  14C, 13C and 12C have 8, 7, and 6 neutrons respectively.  

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It is refracted upon entering a lens
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Am i adopted? and why​
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Epsom salt is commonly purchased in the pharmacy for a variety of uses, anti-inflammatory, laxative, and cosmetic. epsom salt is
Dominik [7]
Epsom salt is MgSO4.
We assume x water of hydration in the crystalline form.

Molecular mass of MgSO4 = 24+32+4*16=120
Molecular mass of MgSO4.xH2O = 120+18x

By proportion, 
2.000/0.977 = (120+18x)/120
Cross multiply
0.977(120+18x) = 120*2.000
from which we solve for x
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=6.980

Answer: there are 7 water of hydration in Epsom salt, according to the experiment.

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4 0
4 years ago
Read 2 more answers
Calculate the molarity of 90.0 mL of a solution that is 0.92 % by mass NaCl. Assume the density of the solution is the same as p
jeka94
Answer is: molarity is 0,155 M.
V(solution) = 90,0 mL = 0,09 L.
ω(NaCl) = 0,92% ÷ 100% = 0,0092.
d(solution) = 1 g/mL.
m(solution) = V(solution) · d(solution).
m(solution) = 90 mL · 1 g/mL = 90 g.
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n(NaCl) = 0,828 g ÷ 58,4 g/mol.
n(NaCl) = 0,014 mol.
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c(solution) = 0,155 mol/L.

8 0
3 years ago
The cation of the salt is sodium ion, and the anion is aurothiosulfate ion. Based on the chemical formula of the salt, what must
marta [7]

Answer:

3-

Explanation:

Sodium aurothiosulfate is a salt with the formula Na₃Au(S₂O₃)₂. The cation of the salt is sodium ion, and the anion is aurothiosulfate ion. We can determine the charge of the aurothiosulfate ion, considering that the sum of the positive and negative charges must be equal to the charge of the compound, which is zero.

3 × Na⁺ + 1 × Au(S₂O₃)₂ⁿ⁻ = 0

3 × +1 + 1 × Au(S₂O₃)₂ⁿ⁻ = 0

Au(S₂O₃)₂ⁿ⁻ = 3-

7 0
3 years ago
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