Question

What is the mass in grams of 1.02 x 1024 atoms manganese (Mn)? a. 0.112 x 101 g c. 9.30 x 10-1g b. 0.169 x 101 g d. 9.31 x101 g Please select the best answer from the choices provided A B C D

Answer 1

I believe you mean 1.02*10^24 so I did

1.02*10^24/(6.02*10^23) * 54.938. I got d) 9.31*10^1 g as my answer.

Answer 2

Answer: Option (d) is the correct answer.

Explanation:

According to Avogadro's number, every 1 mole of a substance contains $6.022 \times 10^{23}$ atoms or particles.

Now, it is given that there are $1.02 \times 10^{24}$ atoms of manganese are present. Hence, calculate its number of moles as follows.

     No. of moles = $\frac{1.02 \times 10^{24}}{6.022 \times 10^{23}}$

                           = 1.69  mol

As we know that, number of moles is equal to mass of a substance divided by its molar mass. Since, molar mass of manganese is 54.93 g/mol.

        No. of moles = $\frac{mass}{\text{molar mass}}$

                1.69 mol = $\frac{mass}{54.93 g/mol}$

                 mass = 93 g

Therefore, we can conclude that the mass in grams of $1.02 \times 10^{24}$ atoms of manganese (Mn) are $9.31 \times 10^{1} g$.