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mylen [45]
3 years ago
9

Triangle A'B'C' is a rotation of triangle ABC by 60 degrees using Q as the center.

Mathematics
1 answer:
deff fn [24]3 years ago
7 0

9514 1404 393

Answer:

  see below

Step-by-step explanation:

When a figure is rotated about a center point, the central angle formed by any point on the figure and the corresponding image point will be the rotation angle. Every image point is the same distance from the center of rotation that the pre-image point was. No lengths or angles are changed: rotation is a "rigid motion", so the rotated figure is congruent with the original.

__

-Angle AQA' is 60 degrees.

-Triangles ABC and A'B'C' are congruent.

-Angle ABC is congruent to angle A'B'C'. (<em>this is one of the angles of the congruent triangles</em>)

-Segment BC is congruent to segment B'C'

-Segment AQ is congruent to segment A'Q.

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The vertices of a triangle are A (2,5) B (1,2) and C (3,1) . Find the coordinates of the image after a dilation with respect to
telo118 [61]

K=2

  • A'=2(2.5)=(4,10)
  • B'=2(1,2)=(2,4)
  • C'=2(3,1)=(6,2)

Translation of 2 units left means change in x

  • A''=(4-2,10)=(2,10)
  • B"=(2-2,4)=(0,4)
  • C"=(6-2,2)=(4,2)

Translation of 1 units up means change in y

  • A'''=(2,10+1)=(2,11)
  • B'''=(0,4+1)=(0,5)
  • C'''=(4,2+1)=(4,3)
5 0
2 years ago
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Jing is helping the kindergarten teacher put together bags of crayons. Each bag has 4 crayons, and 1/4 of the crayons in each ba
wariber [46]

Answer:

A)  \frac{3}{12}

Step-by-step explanation:

Given:

Jing is helping the kindergarten teacher put together bags of crayons.

Each bag has 4 crayons, and 1/4 of the crayons in each bag are green.

What fraction of the crayons in 3 bags are green?

<u>Solution:</u>

1 bag contains number of crayons = 4

1 bag contains number of green crayons = \frac{1}{4} \ of\ 4 = \frac{1}{4}\times4=1

Total number of bags = 3

Total number of crayons in 3 bags = 4 \times 3 = 12

1 bag contains number of green crayons = 1

Total number of green crayons in 3 bags = 1  \times 3 = 3

Fraction of the green crayons out of total = 3 out of 12 = \frac{3}{12}

Therefore, fraction of the crayons in 3 bags are green are  \frac{3}{12}

7 0
4 years ago
Given a≠±b and a^2−b^2/a+b =12, find a−b.
11Alexandr11 [23.1K]
\dfrac{a^2 - b^2}{a+b}  =  12

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Factorise a² - b² :
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\dfrac{(a+b)(a-b)}{a+b}  =  12

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 Crossed out common factors, (x + a) :
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a- b =  12
4 0
4 years ago
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I GIVE YOU BRAINLIEST IF YOU HELP ME WITH THIS. Please guys I beg. I'm the dumbest person on earth.
MrRissso [65]

Answer:

You didn't even post the question how are we supposed to help you

Step-by-step explanation:

8 0
3 years ago
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X-(9x-10)+11=12x+3(-2x+ 1/3)
morpeh [17]
X - (9x - 10) + 11 = 12x + 3(-2x + \frac{1}{3} ) equals x = \frac{10}{7} .

First, simplify brackets. / Your problem should look like: x - 9x + 10 + 11 = 12x + 3(-2x + \frac{1}{3} ). 
Second, simplify x - 9x + 10 + 11 to -8x + 10 + 11. / Your problem should look like: -8x + 10 + 11 = 12x + 3(-2x + \frac{1}{3} ).
Third, simplify -8x + 10 + 11 to -8x + 21. / Your problem should look like: -8x + 21 = 12x + 3(-2x + \frac{1}{3} ).
Fourth, expand. / Your problem should look like: -8x + 21 = 12x - 6x + 1.
Fifth, simplify 12x - 6x + 1 to 6x + 1./ Your problem should look like: -8x + 21 = 6x + 1.
Sixth, add 8x to both sides. / Your problem should look like: 21 = 6x + 1 + 8x.
Seventh, simplify 6x + 1 + 8x to 14x + 1. / Your problem should look like: 21 = 14x + 1.
Eighth, subtract 1 from both sides. / Your problem should look like: 21 - 1 = 14x.
Ninth, simplify 21 - 1 to 20. / Your problem should look like: 20 = 14x.
Tenth, divide both sides by 14. / Your problem should look like: \frac{20}{14} = x.
Eleventh, simplify \frac{20}{14} to \frac{ 10}{7} . / Your problem should look like: \frac{10}{7} = x.
Twelfth, switch sides. / Your problem should look like: x = \frac{10}{7} which is your answer.

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3 years ago
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