let's recall that on the IV Quadrant the x/cosine is positive and the y/sine is negative, and of course the hypotenuse is just a radius unit and therefore never negative.
![\bf \pm\sqrt{15^2-(-7)^2}=a\implies \pm\sqrt{176}=a\implies \stackrel{\textit{IV Quadrant}}{+\sqrt{176}=a} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{\sqrt{176}}}{\stackrel{hypotenuse}{15}}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cpm%5Csqrt%7B15%5E2-%28-7%29%5E2%7D%3Da%5Cimplies%20%5Cpm%5Csqrt%7B176%7D%3Da%5Cimplies%20%5Cstackrel%7B%5Ctextit%7BIV%20Quadrant%7D%7D%7B%2B%5Csqrt%7B176%7D%3Da%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20cos%28%5Ctheta%20%29%3D%5Ccfrac%7B%5Cstackrel%7Badjacent%7D%7B%5Csqrt%7B176%7D%7D%7D%7B%5Cstackrel%7Bhypotenuse%7D%7B15%7D%7D~%5Chfill)
The answer is: [A]: " 120 ft² " .
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Explanation:
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Set up a ratio as a fraction:
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8/3 = 320/x ;
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Cross-multiply:
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8x = 3 * 320 ;
8x = 960 ;
Divide each side of the equation by "8" ;
to isolate "x" on one side of the equation ; and to solve for "x" ;
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8x / 8 = 960 / 8 ;
to get: x = 120 .
The answer is: [A]: " 120 ft² " .
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Answer:
C. The vertical distance of a roller coaster from the ground changes with respect to its horizontal distance from the beginning of the ride.
Step-by-step explanation:
See how the graph is in a "U" shape? That tells us that it first decreases and then goes back up at some point.
The way you would find this answer is to go through each scenario (A, B, C, and D) and think about which thing would make sense to go down and then up.
Answer:
X = 13.13 feet
Step-by-step explanation:
Let the distance between Lila and Mark be x.
Let the distance between Avery and lila be A= 20
Let the distance between Avery and Mark be B= 30
Angle x = 200-180=20°
To solve this question we will use the cosine formula which is
X² = A²+ B² -2ABcosx
X²= 20² + 30² -2(20)(30)cos20
X²=1300-1127.6
X²= 172.4
X= 13.13
