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Shkiper50 [21]
3 years ago
11

How much heat in kJ is released when nitrogen and hydrogen react as below to form 100.g ammonia heat equals-92.2kj

Mathematics
1 answer:
tresset_1 [31]3 years ago
8 0

100g of ammonia releases 271.18 kJ of heat.

<u>Explanation:</u>

Given:

N₂ reacts with H₂

The reaction is:

2N₂ + 3H₂ → 2NH₃ + 92.2 kJ

According to the balanced reaction:

2 X 17g of ammonia releases 92.2 kJ of heat

34g of ammonia releases 92.2 kJ of heat

100g of ammonia will release = \frac{92.2}{34} X 100 kJ of heat

                                                 = 271.18 kJ

Therefore, 100g of ammonia releases 271.18 kJ of heat.

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3y - x = 2<br><br> -2y - x = -18<br><br> x = y =
crimeas [40]

Answer:

3y-x=2

x=−2+3y

y=2/3+x/3

-2y-x=18

y=9-x/2

x=18-2y

Step-by-step explanation:

4 0
3 years ago
On a map, the distance from Akron to Cleveland measures 2 centimeters. What is the actual distance if the scale of the map shows
grin007 [14]
The answer is 60 kilometers.
7 0
4 years ago
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What is value of x ?
zmey [24]
60 degrees,
explanation-
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8 0
4 years ago
A manufacturer makes chocolate squares that have a target weight of 8 g. Quality control engineers sample 30 chocolate squares t
posledela

Using the <em>normal distribution and the central limit theorem</em>, it is found that the power of the test is of 0.9992 = 99.92%.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is \mu = 8.5.
  • The standard deviation is \sigma = 0.87.
  • A sample of 30 is taken, hence n = 30, s = \frac{0.87}{\sqrt{30}} = 0.1588.

The power of the test is given by the probability of a sample mean above 8, which is <u>1 subtracted by the p-value of Z when X = 8</u>, so:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = \frac{8 - 8.5}{0.1588}

Z = -3.15

Z = -3.15 has a p-value of 0.0008.

1 - 0.0008 = 0.9992.

The power of the test is of 0.9992 = 99.92%.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

5 0
2 years ago
80Divided by 3 plz help
mojhsa [17]

Answer:

Your answer is 26.667

hope this helps

8 0
3 years ago
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