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Maurinko [17]
3 years ago
10

How are tides created on earth?

Chemistry
2 answers:
N76 [4]3 years ago
4 0
The gravitational interaction between the earth and the moon
AVprozaik [17]3 years ago
3 0
Tides are caused by the gravitational interaction between the Earth and the .
The gravitational attraction of the moon causes the oceans to bulge out in the direction of the moon.

Hope it helped!
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Select the correct pronoun.
ololo11 [35]
These are some pronouns to help you!

<span>I, me, he, she, herself, you, it, that, they, each, few, many, who, whoever, whose, someone, everybody.
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It is who! :D
I hope this helps!
3 0
3 years ago
Read 2 more answers
The minimum amount of energy that has to be added to start a reaction is the
Svetllana [295]
The minimum amount of energy that has to be added to start a reaction is the activation energy, which starts the reaction. It activates it. 
7 0
3 years ago
How many moles of Ca[OH]2 are present in 80.0 g of Ca[OH]2?​
artcher [175]

Answer:

1.08mol

Explanation:

moles = reacting mass/ molecular weight

reacting mass = 80.0g molecular weight of Ca[OH]2= 40 + 2(16 +1) = 74g/mol

mole = 80.0/74 = 1.08mol

4 0
3 years ago
Balance each chemical equation.<br> Hg2(C2H3O2)2(aq)+KCl(aq)→Hg2Cl2(s)+KC2H3O2(aq)
Ira Lisetskai [31]

Answer:

Explanation:

When potassium chloride reacts with lead acetate in aqueous medium, it gives white precipitate of lead chloride and potassium acetate in aqueous medium as a product.

As shown in chemical reaction given below:

4 0
2 years ago
Consider the following chemical equilibrium: CaCO3 (s) Cao (s)+cO2 (g) Now write an equation below that shows how to calculate K
True [87]

Answer:

Kc = Kp/(RT)

Explanation:

Let's consider the following chemical equilibrium:

CaCO₃(s) ⇄ CaO(s) + CO₂(g)

Given the pressure equilibrium constant Kp = pCO₂

We can calculate the concentration equilibrium constant (Kc) using the following expression.

Kc = Kp/(RT)^{\Delta n(g)}

where,

R is the ideal gas constant

T is the absolute temperature

Δn(g) = moles of gaseous products - moles of gaseous reactants = 1 - 0 = 1

The expression for this reaction is:

Kc = Kp/(RT)

4 0
3 years ago
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