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pickupchik [31]
3 years ago
9

A teacher makes the following statement.

Chemistry
2 answers:
Natali [406]3 years ago
6 0

Answer:

The correct answer is option a.

Explanation:

According the question, boiling points of different liquids are discussed which means that if we take all these liquids in single mixture we can separate them from each other on the basis of their difference in boiling point. And the technique which employs this principle is distillation process.

Hence, we can say teacher is most likely talking about distillation of a mixture of oils.

Distillation is a process which is used to separate mixture of different liquids from each other. In this process, during the course of boiling of mixture liquid compound with lower boiling points vaporizes first leaving behind the liquid with higher boiling point behind.

And vapors of boiled liquid are condensed down in a separate container for the collection.

DedPeter [7]3 years ago
5 0
I believe the correct answer from the choices listed above is option A. The topic that the teacher is talking about would be distillation of a mixture. Gasoline is processed by distillation. Hope this answers the question. Have a nice day.
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C. to find housing.

Explanation:

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Ca (ClO) 2<br> Spell out the full name of the compound.
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Copper(II) sulfide is formed when copper and sulfur are heated together. In this reaction,
storchak [24]

Answer:

The mass of copper(II) sulfide formed is:

= 81.24 g

Explanation:

The Balanced chemical equation for this reaction is :

Cu(s) + S\rightarrow CuS

given mass= 54 g

Molar mass of Cu = 63.55 g/mol

Moles = \frac{given\ mass}{Molar\ mass}

moles=\frac{54}{63.55}

Moles of Cu = 0.8497 mol

Given mass = 42 g

Molar mass of S = 32.06 g/mol

Moles = \frac{given\ mass}{Molar\ mass}

moles=\frac{42}{32.06}

Moles of S = 1.31 mol

Limiting Reagent :<em> The reagent which is present in less amount and consumed in a reactio</em>n

<u><em>First find the limiting reagent :</em></u>

Cu + S\rightarrow CuS

1 mol of Cu require = 1 mol of S

0.8497 mol of Cu should require  = 1 x 0.8497 mol

= 0.8497 mol of S

S present in the reaction Medium = 1.31 mol

S Required  = 0.8497 mol

S is present in excess and <u>Cu is limiting reagent</u>

<u>All Cu is consumed in the reaction</u>

Amount Cu will decide the amount of CuS formed

Cu + S\rightarrow CuS

1 mole of Cu  gives = 1 mole of Copper sulfide

0.8497 mol of Cu =  1 x 0.8497 mole of Copper sulfide

= 0.8497

Molar mass of CuS = 95.611 g/mol

Moles = \frac{given\ mass}{Molar\ mass}

0.8497 = \frac{given\ mass}{95.611}

Mass of CuS = 0.8497 x 95.611

= 81.24 g

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What is the m∠L? 45° 54° 40° 52°
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Answer:

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Answer:

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