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cupoosta [38]
3 years ago
12

A sample of gas is inside of a rigid container with fixed volume of 350mL. The initial pressure of the system is 366kPa, and the

initial temperature is 88 degrees Celsius. How would the pressure of the system change if the temperature was increased to 110 degrees Celsius?
Chemistry
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

457.5kPa

Explanation:

Given data

V1=V2=350mL  (<em>fixed volume</em> )

P1=366kPa

T1= 88 degrees Celsius

P2=??

T2= 110 degrees Celsius

For the general gas equation

P1V1/T1= P2V2/T2

V1=V2

P1/T1= P2/T2

Substitute

366/88= P2/110

Cross multiply we have

P2*88=366*110

P2*88= 40260

P2= 40260/88

P2= 457.5 kPa

Hence the pressure will change to 457.5kPa

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Answer:

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A sample of a gas at room temperature occupies a volume of 29.0 L at a pressure of 562 torr . If the pressure changes to 2810 to
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Answer:

The new volume will be 5.80 L

Explanation:

Step 1: Data given

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The pressure changes to 2810 torr = 2810 /760 atm = 3.697368 atm

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Step 2: Calculate the new volume

P1*V1 = P2*V2

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⇒with V1 = the initial volume = 29.0 L

⇒with P2 = the increased pressure = 3.697368 atm

⇒with V2 = The new volume = TO BE DETERMINED

0.739474 atm * 29.0 L = 3.697368 atm * V2

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V2 = 5.80 L

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