Calculate the percent composition of muscovite mica. Its chemical

Chemistry

1 answer:

Vikki [24]3 years ago

7 0

Answer:

Explanation:

(KF)2(Al2O3)3(SiO2)6(H2O)

molecular formula

K₂F₂Al₆Si₆O₂₂H₂

2 x 39 + 2 x 19 + 6 x 27 + 6 x 28 + 22 x 16 + 2 x 2

= 78 + 38 + 162+ 168+ 352+ 4

= 802

Percentage of K = 78 x 100 / 802

= 9.72 %

Percentage of F = 38 x 100 / 802

= 4.74 %

Percentage of Al = 162 x 100 / 802

= 20.2 %

Percentage of Si = 168 x 100 / 802

= 20.9 %

Percentage of O = 352 x 100 / 802

= 43.9 %

Percentage of H = 4 x 100 / 802

= .54 %

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What's the mass of methanol?

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zlopas [31]

Answer:

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Explanation:

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$\rho = \frac{m}{V}$

The specific volume (ν) of a substance is the ratio of its mass to its volume. We can see that it is the reciprocal of density and an intrinsic property of matter as well. Therefore, the units of specific volume are m³/kg.

$\nu = \frac{V}{m}=\frac{1}{\rho }$