Well it is true if the problem is the right with the right answer. If not you have a false eqaution.
C, i dont know dont use my answer unless you know
Answer:
108
Step-by-step explanation:
do u guys stay on this and text on this
Answer:
4) v=kx^2/y^3
2= k(4^2)/(3^3)
2 =k16/27
k = 2(27/16) = 27/8
v = (27/8)(3^2)/(2^3 = (27/8)(9/8) = 243/64
v = 243/64 when x=3 and y=2
Step-by-step explanation:
here
Answer:
(a)18
(b)1089
(c)Sunday
Step-by-step explanation:
The problem presented is an arithmetic sequence where:
- First Sunday, a=1
- Common Difference (Every subsequent Sunday), d=7
We want to determine the number of Sundays in the 120 days before Christmas.
(a)In an arithmetic sequence:

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.
Therefore, Aldsworth advertised 18 times.
(b)Next, we want to determine the sum of the first 18 terms of the sequence
1,8,15,...

The sum of the numbers of days published in all the advertisements is 1089.
(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.