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2 years ago

14

You found a job that pays $15 per hour. After working for one year, you will get a 4% raise. What will be your new pay rate afte

r one year

1 answer:

hammer [34]2 years ago

4 0

It will be 60 because you multiple 15 by 4

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A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4

Vladimir79 [104]

Answer:

The time interval when $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

$V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)$

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

$V_Q(t) \geq 60$ between $0 \leq t \leq 4$

The schematic free body graphical representation of the above illustration was attached in the file below and the point when $V_Q(t) \geq 60$ is at 4 is obtained in the parabolic curve.

So, $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

Taking the integral of the time interval in order to determine the distance; we have:

distance = $\int\limits^{3.519}_{1.866} {V_Q(t)} \, dt$

= $\int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt$

= By using the Scientific calculator notation;

distance = 106.109 m

4 0

3 years ago

Given 11 different natural numbers, none greater than 20. Prove that two of these can be chosen, one of which divides the other.

frosja888 [35]

Answer:11 honestly have no idea but im going to give my best answer it is 31

4 0

3 years ago

Read 2 more answers

Consider a local community of a rock chucks in Wyoming that are increasing at a rate of 11% per month. Using the Rule of 70, ans

natka813 [3]

I am not good at math or I would help :/

8 0

3 years ago

Can someone help me and explain? I will mark brainlest. ♡

Sedbober [7]

Answer:

$p'(4) = -3$

$q'(8) = \frac{1}{4}\\$

Step-by-step explanation:

For p'(4):

$p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)$

$p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3$

For q'(8):

$q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}$

$q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}$

4 0

3 years ago

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A skier is trying to decide whether or not to buy a season ski pass. A daily pass costs $68. A season ski pass costs $300. The

lina2011 [118]

first, ignore the rent for the skies. we could add it to both, but since it's the same, it would not change the number of days here.

this information is meant to test your decision making on what's important for the question.

now just ask how often you can pay $68 dollars per day while staying below 300 in total, you can just count it up.

68, 136, 204, 272, 340

its 4 days

for 5 days or more, the season pass is the better option

5 0

2 years ago