55 adult tickets. Set up 2 equations: c+a=125 and 6.1c+9.4a=944. Isolate either variable from first equation and plug into second to find that 55 adult tickets were sold and 70 children’s tickets
7,265 is the average of those two numbers, though i am not sure what the sign that is mentioned is
We know that you have 83$ in your bank account.
Okay so what is 15+8=23 So that means you get 23$ per week.
Now what is 83+23=106
106+23=129
129+23=152
152+23=175
Now that was four 23's
That means it would take 4 weeks for you to have 175 dollars in your bank account.
Hope this helped.
Answer:
<em>The answers are for option (a) 0.2070 (b)0.3798 (c) 0.3938
</em>
Step-by-step explanation:
<em>Given:</em>
<em>Here Section 1 students = 20
</em>
<em>
Section 2 students = 30
</em>
<em>
Here there are 15 graded exam papers.
</em>
<em>
(a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070
</em>
<em>
(b) Here if x is the number of students copies of section 2 out of 15 exam papers.
</em>
<em> here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15
</em>
<em>Then,
</em>
<em>
Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798
</em>
<em>
(c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1)
</em>
<em>
so,
</em>
<em>
Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938
</em>
<em>
Note : Here the given distribution is Hyper-geometric distribution
</em>
<em>
where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>
Answer:
the 2nd option f(-4) = g(-4) and f(0) = g(0)
Step-by-step explanation:
the right answer was the same x and sampe y. it means in their intersection for both f(x) anad g(x)
so the correct answer is f(0) = g(0) and f(-4) = g(-4)
