1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Finger [1]
3 years ago
14

A force vector points due east and has a magnitude of 140 newtons. A second force is added to . The resultant of the two vectors

has a magnitude of 420 newtons and points along the (a) east/ (b) west line. Find the magnitude and direction of . Note that there are two answers. (a) Number newtons (b) Number newtons
Physics
1 answer:
ale4655 [162]3 years ago
8 0

Answer:

(a) When the resultant force is pointing along east line, the magnitude and direction of the second force is 280 N East

(b)  When the resultant force is pointing along west line, the magnitude and direction of the second force is 560 N West

Explanation:

Given;

a force vector points due east, F_1 = 140 N

let the second force = F_2

let the resultant of the two vectors = F

(a) When the resultant force is pointing along east line

the second force must be pointing due east

F = F_1 + F_2\\\\F_2 = F - F_1\\\\F_2 = 420 \ N - 140 \ N\\\\F_2 = 280 \ N

F_2 = 280 \ East

(b) When the resultant force is pointing along west line

the second force must be pointing due west and it must have a greater magnitude compared to the first force in order to have a resultant in west line.

F = F_2 - F_1\\\\F_2 = F + F_1\\\\F_2 = 420 \ N + 140 \ N\\\\F_2 = 560 \ N

F_2 = 560 \ West

You might be interested in
How big is the international space station?
oee [108]
The dimensions of the completed ISS research facility will be approximately 356 feet (109 meters) by 240 feet (73 meters), or slightly larger than a football field. the ISS weighes around 450 tons (408,000 kg), or 450 times the weight of an average car.
3 0
3 years ago
Which statement about gravity is true?
SVETLANKA909090 [29]

Out of the given options, ‘it is described as a fundamental force and therefore does not depend on other forces’ is the true statement about gravity.

Answer: Option B

<u>Explanation: </u>

As we all know that there are four fundamental forces existing in the universe- Electromagnetic force, strong forces, weak forces and the gravitational force.

These are the forces that don’t depend on any other physical force to draw a considerable impact on the physical objects. The gravitational force can be defined as,

                     F=G \times \frac{m_{1} m_{2}}{r^{2}}

Where,

G = Gravitational Constant

m_{1} , m_{2} = Masses of two substances under consideration

R = distance between the two substances.

Looking upon the formula of gravitational force we can easily estimate that the gravitational force relies on the mass of substances and the relative distance between them. There is no factor than the air friction that hinders the gravitational force and that too in a negligible amount.

5 0
2 years ago
Using the graph, describe what is happening between 4 and 6 seconds. The object is moving away from the origin at a constant vel
Hunter-Best [27]

The position in the graph between 4 - 6 seconds is the region of constant velocity.

<h3>What is constant velocity?</h3>

The term constant velocity refers to the period in the graph when the velocity is not changing with time. As such, the graph is shown to be a flat portion at such a point.

Hence, it follows that the position in the graph between 4 - 6 seconds is the region of constant velocity.

Learn more about constant velocity:brainly.com/question/17014780

#SPJ1

8 0
2 years ago
4. What is the electric field strength (E) at a distance of 0.50 m from a 1.00×10°C charge?
Romashka-Z-Leto [24]

Answer:

3.6*10¹⁰N/C

Explanation:

The formula for Electric field strength is expressed as:

E = kQ/r²

k is the coulombs constant = 9*10^9Nm²/C²

Q is the charge = 1.00×10°C

r is the distance = 0.50m

Substitute the parameters into the formula as shown:

E = kQ/r²

E =  9*10^9(1)/0.5²

E =  9*10^9/0.25

E = 36*10^9

<em>E = 3.6*10¹⁰N/C</em>

<em>Hence  the electric field strength is 3.6*10¹⁰N/C </em>

3 0
3 years ago
Two water jets are emerging from a vessel at a height of 50 centimeters and 100 centimeters. If their horizontal velocities at t
scoundrel [369]

Answer: The correct answer is option (D).

Explanation:

Vertical distance  of first water jet = y_1=50 cm

Vertical distance of second water jet = y_2=100 cm

Horizontal velocity of first water jet =u_y_ 1=1 m/s

Horizontal velocity of second water jet = u_y_2=0.5 m/s

Vertical distance of first water jet:

y_1=(u_y_1)t_1+\frac{1}{2}gt_1^2

u_y_1=0,(u_y_1)t_1=0

t_1=\sqrt{\frac{2y_1}{g}}...(1)

Similarly, Vertical distance of second water jet:

y_2=(u_y_2)t_2+\frac{1}{2}gt_2^2

u_y_2=0,(u_y_2)t_2=0

t_2=\sqrt{\frac{2y_2}{g}}...(2)

Horizontal distance of first water jet:

x_1=(u_x_1)t_1+\frac{1}{2}at_1^2

There is no acceleration in horizontal direction.

a=0,at_1^2=0

x_1=(u_y_1)t_1...(3)

Horizontal distance of second water jet:

x_2=(u_x_2)t_2+\frac{1}{2}at_2^2

a=0,at_2^2=0

x_2=(u_x_2)t_2...(4)

On dividing (3) and (4):

\frac{x_1}{x_2}=\frac{(u_y_1)t_1}{(u_y_2)t_2}

\frac{x_1}{x_2}=\frac{u_y_1}{u_y_2}\times\frac{\sqrt{\frac{2y_1}{g}}}{\sqrt{\frac{2y_2}{g}}}}=\frac{u_y_1}{u_y_2}\sqrt{\frac{y_1}{y_2}}

(from (1) and (2))

\frac{x_1}{x_2}=\frac{1 m/s}{0.5 m/s}\sqrt{\frac{50 cm}{100 cm}}=1.41:1

Hence, the correct answer is option (D).


6 0
3 years ago
Other questions:
  • There is a(n) __________ relationship between an object's weight and its mass.
    10·1 answer
  • At time t = 1, a particle is located at position (x, y) = (5, 2). If it moves in the velocity field F(x, y) = xy − 1, y2 − 11 fi
    5·1 answer
  • James threw a ball vertically upward with a velocity of 41.67ms-1 and after 2 second David threw a ball vertically upward with a
    7·1 answer
  • An electric current is passed through water and bubbles start forming.What is a logical conclusion for the bubbles?
    9·2 answers
  • A turntable is designed to acquire an angular velocity of 32.4 rev/s in 0.5 s, starting from rest.
    13·2 answers
  • A LED light source contains a 0.5-Watts GaAs (Eg =1.43 eV) LED. Assuming that 0.12% of the electric energy is converted to emiss
    8·1 answer
  • LINK OR PDF = REPORT
    9·2 answers
  • 4. What is the period of the microwaves in the above question?
    8·1 answer
  • A car is traveling at a speed of 20m/s and has a mass of 1200kg how much kinetic energy does it have
    6·1 answer
  • How does the long shape of submarines and torpedoes reduce the dragthey feel when moving under water?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!