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Finger [1]
3 years ago
14

A force vector points due east and has a magnitude of 140 newtons. A second force is added to . The resultant of the two vectors

has a magnitude of 420 newtons and points along the (a) east/ (b) west line. Find the magnitude and direction of . Note that there are two answers. (a) Number newtons (b) Number newtons
Physics
1 answer:
ale4655 [162]3 years ago
8 0

Answer:

(a) When the resultant force is pointing along east line, the magnitude and direction of the second force is 280 N East

(b)  When the resultant force is pointing along west line, the magnitude and direction of the second force is 560 N West

Explanation:

Given;

a force vector points due east, F_1 = 140 N

let the second force = F_2

let the resultant of the two vectors = F

(a) When the resultant force is pointing along east line

the second force must be pointing due east

F = F_1 + F_2\\\\F_2 = F - F_1\\\\F_2 = 420 \ N - 140 \ N\\\\F_2 = 280 \ N

F_2 = 280 \ East

(b) When the resultant force is pointing along west line

the second force must be pointing due west and it must have a greater magnitude compared to the first force in order to have a resultant in west line.

F = F_2 - F_1\\\\F_2 = F + F_1\\\\F_2 = 420 \ N + 140 \ N\\\\F_2 = 560 \ N

F_2 = 560 \ West

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