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2 years ago

Có hai bình chứa được nối với nhau bằng một ống nhỏ có thể tích không đáng kể. Một

Physics

1 answer:

earnstyle [38]2 years ago

5 0

Answer:

a b c d e f g h I love you will you marry me

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A plastic rod that has been charged to − 15 nC touches a metal sphere. Afterward, the rod's charge is − 5.0 nC.

Natali5045456 [20]

Answer:

B) electrons transferred from sphere to rod.

(2) 1.248 x 10¹¹ electrons were transferred

Explanation:

Given;

initial charge on the plastic rod, q₁ = 15nC

final charge on the plastic rod, q₂ = - 5nC

let the charge acquired by the plastic rod = q

q + 15nC = -5nC

q = -5nC - 15nC

q = -20 nC

Thus, the plastic rod acquired excess negative charge from the metal sphere.

Hence, electrons transferred from sphere to rod

B) electrons transferred from sphere to rod.

2) How many charged particles were transferred?

1.602 x 10⁻¹⁹ C = 1 electron

20 x 10⁻⁹ C = ?

= 1.248 x 10¹¹ electrons

Thus,1.248 x 10¹¹ electrons were transferred

7 0

3 years ago

What will happen if we put a magnet in cold water

gayaneshka [121]

Answer:

cold water strengthens the magnetic attractive force.

Explanation:

The molecules within the magnet will move slower because they have less kinetic energy,so there is less vibration within the magnets molecules.

8 0

2 years ago

6) what is ararge of speed

irina [24]

Answer:

in everyday use and in kinematic the speed of an object is the magnitude of the change of its position it is thus a scalar quantity

5 0

3 years ago

A sphere of plastic of radius = .100 m is completely immersed in water. The density of the plastic is 600 kg/m3. Since the plast

tekilochka [14]

To solve this problem we need to use the proportional relationships between density, mass and volume, together with Newton's second law.

The force can be described as

$F = ma \rightarrow mg$

Where,

m = Mass

g = Gravitational acceleration

At the same time the Density can be defined as

$\rho = \frac{m}{V} \rightarrow m = \rho V$

Where,

m = mass

V = Volume

Replacing the value of the mass at the equation of Force we have,

$F = \rho V g$

Since the difference between the two forces gives us the total Force then we have to

$F_T = F_w - F_p$

Where

$F_w =$ Force of the water

$F_p$ = Force of plastic

Therefore with the values for this force we have,

$F_T = \rho_w Vg - \rho_p Vg$

$F_T = Vg(\rho_w - \rho_p)$

$F_T = (\frac{4}{3} \pi r^3) g(\rho_w - \rho_p)$

$F_T = (\frac{4}{3} \pi (0.1)^3) (9.8)(1000 - 600)$

$F_T = 16.412 N$

Therefore the tension in the thread is 16.412N

3 0

3 years ago

If this decay has half-life of 2 years, how many years would it take for 10.8 g Protactinium-231 to remain given an initial mass

sergij07 [2.7K]

Answer:

Time = 6 years

Explanation:

First, we will calculate the no. of half life periods required to reduce the mass of Protactinium to the given value:

$m' = \frac{m}{2^{n} } \\\\2^n = \frac{m}{m'}$

where,

n = no. of half-life periods = ?

m = initial mass = 86.3 g

m' = remaining mass = 10.8 g

Therefore,

$2^n = \frac{86.3\ g}{10.8\ g}\\\\2^n = 8\\2^n = 2^3$

Since the bases are the same. Therefore equating powers:

n = 3

Now we calculate the time:

$Time = (n)(Half-Life)\\Time =(3)(2\ years)$

<u>Time = 6 years</u>

3 0

3 years ago