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vaieri [72.5K]
3 years ago
14

Consider a small child sliding down two differently shaped slides that have the same coefficient of kinetic friction. How must t

he second slide be shaped to provide the same change in gravitational potential energy of the child-Earth system but more change in kinetic energy for the child while they slide down
Physics
1 answer:
timama [110]3 years ago
6 0

Answer:

Having a bigger angle above the horizontal

Explanation:

Applying the energy conservation theorem:

K_1+U_1+W_{ext}=K_2+U_2

The kinetic energy is reduced because of the work done by the friction force.

The friction force is given by:

F_f=F_N*\µ

so the friction force depends on the Normal force, because the slide has an angle the normal force is given by:

F_N=m.g*cos(\theta)

So when the angle of the slide is bigger, the friction force decreases, for example:

for 45 degrees:

F_N=m.g*cos(45)\\F_N=0.70(m.g)\\

for 75 degrees:

F_N=m.g*cos(75)\\F_N=0.26(m.g)\\

as you can see if the angle is bigger above the horizontal, the friction force is reduced and so the work done by that force. We didn't have to change the height of the slide, so the potential gravitational energy remains the same.

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The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.4 square inches. If a force of 6.4 lb
Anit [1.1K]

Answer:

The force applied on one wheel during braking = 6.8 lb

Explanation:

Area of the piston (A) = 0.4 in^{2}

Force applied on the piston(F) = 6.4 lb

Pressure on the piston (P) = \frac{F}{A}

⇒ P = \frac{6.4}{0.4}

⇒ P = 16 \frac{lb}{in^{2} }

This is the pressure inside the cylinder.

Let force applied on the brake pad = F_{1}

Area of the brake pad (A_{1})= 1.7 in^{2}

Thus the pressure on the brake pad (P_{1}) =  \frac{F_{1} }{A_{1} }

When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.

⇒ P = P_{1}

⇒ 16 = \frac{F_{1} }{A_{1} }

⇒ F_{1} = 16 × A_{1}

Put the value of A_{1} we get

⇒ F_{1} = 16 × 1.7

⇒ F_{1} = 27.2 lb

This the total force applied during braking.

The force applied on one wheel = \frac{F_{1} }{4} = \frac{27.2}{4} = 6.8 lb

⇒ The force applied on one wheel during braking.

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How does the cell membrane work to protect the cell?
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It forms a protective and adaptive barrier around a cell and this keeps various bacterial and viral intruders out. They also help in keeping cell systems inside the cell. The shell absorbs viruses and bacteria for nutrients when they do not have a certain strand to get inside the cell or trick it otherwise. Hope this helped!
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