Explanation:
feed the grass
evaporate
reclaimed
fall in the sand( bunkers under ground)
if this does not help, please be more specific
The vacuoles are the answer
Answer:
1.332 Molar is the molarity of the glucose solution.
Explanation:
Molarity of the solution is the moles of compound in 1 Liter solutions.

Mass of glucose = 60.00 g
Molar mass of glucose = 180.2 g/mol
Volume of the solution = V = 250.0 mL = 0.250 L
(1 mL = 0.001 L)

1.332 Molar is the molarity of the glucose solution.
Answer:
12.2329 atm
Explanation:
Applying
PV = nRT.................... Equation 1
Make P the subject of the equation
P = (n/V)RT................ Equation 2
Where P = Osmotic pressure, (n/V) = Molarity of urea, T = Temperature, R = molar gas constant.
From the question,
Given: (n/V) = 0.5 M, T = 25°C = (273+25) = 298 K, R = 0.0821 Latm/mol.K
Substitute these values into equation 2
P = (0.5)(298)(0.0821)
P = 12.2329 atm