Answer:
1008.0 kJ.
Explanation:
- Firstly, we need to calculate the no. of moles of 88.0 g of propane:
<em>n = mass/molar mass </em>= (88.0 g)(/(44.0 g/mol) = <em>2.0 mol.</em>
∴ The combustion of 2.0 moles of propane produces 4032.0 kJ.
<em><u>Using cross multiplication: </u></em>
The combustion of 2.0 moles of propane produces → 4032.0 kJ.
The combustion of 0.5 moles of propane produces → ??? kJ.
<em>∴ The amount of heat released for the combustion of 0.5 moles of propane </em>= (4032.0 kJ)(0.5 mol)/(2.0 mol) = <em>1008.0 kJ.</em>
Answer:
The answer to your question is the letter d. S
Explanation:
Data
Change of +4 in the oxidation number
Chemical reaction
K₂Cr₂O₇ + H₂O + S ⇒ KOH + Cr₂O₃ + SO₂
Process
1.- Calculate the oxidation numbers following the rules.
Some rules
H = +1 O = -2 Alkali metals = + 1 Alkali earth metals = +2
K₂⁺¹Cr₂⁺⁶O₇⁻² + H₂⁺¹O⁻² + S⁰ ⇒ K⁺¹O⁻²H⁺¹ + Cr₂⁺³O₃⁻² + S⁺⁴O₂⁻²
Elements that changed their oxidation numbers
Cr₂⁺⁶ ---------------- Cr₂⁺³
S⁰ --------------- S⁺⁴
In balancing chemical equations, all you need to do is make it so that you have the same number of each element on both sides of the eqtn (if I have 5C on the left, I have to have 5C on the right — an element can’t magically appear or disappear); that being said:
(2)C2H6 + 7O2 ➡️ 6H2O + 4CO2
(12)HClO4 + P4O10 ➡️ 4H3PO4 + (6)Cl2O7
2N2 + (5)O2 + 2H2O ➡️ 4HNO3
(3)CaCl2 + 2Na3PO4 ➡️ (1)Ca3(PO4)2 + 6NaCl
4FeS + 7O2 ➡️ 2Fe2O3 + 4SO2
Answer:
C
Explanation:
Metals are good conductors of heat
