If it has 2 or more non-metals as well as a metal
Answer:
C
Explanation:
Because 2 x n square gives the total energy level been absorbed = 2 x16
=32
Answer:
mass of oxygen gas in Kg = 15.0Kg
Explanation:
Volume of air in the room = 4.0m*5.0m*2.5m = 50m³
volume of oxygen in the room = 21/100 * 50m³ = 10.5m³
using the ideal gas equation; PV=nRT
number of moles of oxygen gas, n = PV/RT
At STP, P = 1atm, V = 10.5m³ = (10.5*1000)dm³ = 10500dm³, R = 0.082 atmdm³K⁻¹mol⁻¹, T = 273K
n = 1 * 10500/ (273 *0.082)
n = 469.04 moles
mass of oxygen gas in Kg = (no of moles * molar mass)/1000
molar mass of oxygen gas = 32g
mass of oxygen gas in Kg = (469.04 * 32)/1000
mass of oxygen gas in Kg = 15.0Kg
Answer:
Explanation:
We are asked to find the pressure of a gas in a can given a change in temperature. We will use Gay-Lussac's Law, which states the pressure of a gas is directly proportional to the temperature. The formula for this law is:
Initially, the gas in the aerosol can has a pressure of 3.10 atmospheres at a temperature of 25 degrees Celsius.
The temperature is increased to 52 degrees Celsius, but the pressure is unknown.
We are solving for the new pressure, so we must isolate the variable . It is being divided by 52 degrees Celsius. The inverse operation of division is multiplication, so we multiply both sides of the equation by 52 °C.
The units of degrees Celsius cancel.
The original values of pressure and temperature have 2 and 3 significant figures. Our answer must be rounded to the least number of sig figs, which is 2. For the number we calculated, that is the tenths place. The 4 in the hundredth place tells us to leave the 4 in the tenths place.
The gas pressure in the can at 52 degrees Celsius is approximately <u>6.4 atmospheres.</u>