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azamat
3 years ago
9

If Hector is 8 years old and Mary is 3 years old, how old will Mary be when Hector is 16? Can I use proportional reasoning in he

re
Mathematics
1 answer:
Arada [10]3 years ago
4 0

Answer:

Step-by-step explanation:

H=8

M=3

=>difference is 5 years

H=16

=>M=16+5=21

will be nice if you give me brainlies.Good luck!

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Maggie buys 5 apples and 4 oranges for $10 and Lynn buys 5 apples and 5 oranges for $11. What is the price for an apple and what
nlexa [21]
Make 2 eqn, let a be apples and o be oranges:

1. 5a + 4o = 10
2. 5a + 5o = 11

set up an elimination:
1. minus 2.
5a + 4o = 10
- 5a + 5o = 11
____________
o = 1

sub “o” into one of the eqn

5a + 5(1) = 11
5a = 11-5
5a = 6
a = 6/5
a = 1.2

therefore, an orange costs $1.00 and an apple costs $1.20

6 0
3 years ago
Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

3 0
3 years ago
Which of the following ratlos is not equivalent to 6:10?
Len [333]

Answer:

24/45 or 9/15

Step-by-step explanation:

none of these is equivalent to 6:10

7 0
3 years ago
2х + Зу = 3 y = 8 – 3х​
GaryK [48]

Answer: Point form: ( 3 , -1 )

              Equation form: X= 3 and Y= -1

Step-by-step explanation:

6 0
2 years ago
The temperature in Waterloo was − 5°C at sunrise. By noon the temperature had risen by 12 Celsius degrees. What was the temperat
allochka39001 [22]
The answer is 7° Celsius.
6 0
3 years ago
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