Answer:
well I am going to say A
Step-by-step explanation:
it
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13/15 of her allowance was spent in total.
To solve this, you'd need to find the least common denominator (LCD) so that both fractions have the same number on the bottom. In this case, the first number that you could get with 5 and 3 was 15.
Next, you'd have to multiply the numerator by the same amount as the denominator, so that the fractions are proportionate. So, for 1/5, since we had to multiply 5 by 3 to get 15, we'd multiply 1 by 3 as well, giving us 3/15. Doing the same with 2/3, we'd get 10/15.
Then, you add the two fractions together (10/15 + 3/15 = 13/15).
Now, in any other case, you could probably simplify the fraction after you've solved the problem. If we got 12/15 instead of 13/15, then we could simplify that to 4/5, since both 12 and 15 are divisible by 3. But in this case, this is the simplest form of that fraction.
Hope this helped!!!
Answer:
(I) yessssssssssssssssssssssss
Answer:
Step-by-step explanation:
For a. you are asked to evaluate f(0). This is a piecewise function with different domains for each piece of the function. You can only evaluate f(0) in the function that has a domain that allows 0 in it. In the first domain, it says
x < -3. 0 is not less than -3, so 0 is not in that domain, so you will not use that "piece" of the function to evaluate f(0).
In the next domain, it says that x is greater than or equal to -3 and less than 0. Again, 0 is not included in that domain, so we can't use that "piece" of the function to evaluate f(0).
The last domain says that x is greater than OR EQUAL TO 0, so this is where we evaluate f(0):
f(0) = -0 - 4 so
f(0) = -4
When we want to evaluate f(2), we follow the same rules. Find the piece of the function that allows 2 in its domain. That's the middle piece:
f(2) = 2(2) - 6 so
f(2) = -2
Exe.1
a. 0.1+0.1<1, 0.2+0.2 <1, 0.3+0.3 <1, 0.4+0.4 <1, 0.41+0.41 <1
b.0.5+0.5, 0.2+0.8, 0.6+0.4, 0.3+0.7, 0.9+0.1
c. 0.9+0.9, 0.8+0.8, 0.7+0.7, 0.6+0.60, 0.61+0.61
exe 2
8.55 and 2.22, 7.34 and 1.01, 7.35 and 1.02, 7.36 and 1.03, 7.37 and 1.04
exe 3
the two numbers are both decimals less than one. example: 0.01 and 0.1
