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Ghella [55]
3 years ago
11

What is the following quotient? Sqr root 6+ sqr root 11/sqr root 5 + sqr root of 3

Mathematics
1 answer:
adoni [48]3 years ago
4 0

Answer:4.31

Step-by-step explanation:

You might be interested in
35 percent of the students are boys which is 259 find the total number of the students and girls​
Amanda [17]

Answer:

740 total students, 481 total girls

Step-by-step explanation:

Let x be the total number of students and y be the total number of girls

x -

You know that 35% of the students is 259 students. If you convert this into algebra, you can write : 0.35x = 259, after simplifying, you know that x = 740.

y-

You know that 35% of the students are boys, so 65% must be girls. You can say that 65% of x is y and write the equation 0.65(740)=y. After simplifying, you can see that y = 481.

I hope this helps :)

5 0
3 years ago
Read 2 more answers
Which of the following statements is NOT true?
faltersainse [42]

Answer:

A?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
♦️ANSWER NEEDED QUICK, SHOW YOUR WORK♦️
Crank

Answer:

1 and 1/3 yard

Step-by-step explanation:

200 divided by 150 is equal to 4 divided by 3

using a fraction calculator i did

4       3            1

-    /   -     =   1  -

1       1              3

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B27%7D%20%5Ctimes%20%20%20%5Csqrt%5B3%5D%7B16%7D%20%20%3D%20%20%20%20" id="
gtnhenbr [62]
I hope it helps. ....................

7 0
3 years ago
Farmers know that driving heavy equipment on wet soil compresses the soil and injures future crops. Here are data on the "penetr
Greeley [361]

Answer:

Step-by-step explanation:

Hello!

To see if driving heavy equipment on wet soil compresses it causing harm to future crops, the penetrability of two types of soil were measured:

Sample 1: Compressed soil

X₁: penetrability of a plot with compressed soil.

n₁= 20 plots

X[bar]₁= 2.90

S₁= 0.14

Sample 2: Intermediate soil

X₂: penetrability of a plot with intermediate soil.

n₂= 20 (with outlier) n₂= 19 plots (without outlier)

X[bar]₂= 3.34 (with outlier) X[bar]₂= 2.29 (without outlier)

S₂= 0.32 (with outlier) S₂= 0.24 (without outlier)

Outlier: 4.26

Assuming all conditions are met and ignoring the outlier in the second sample, you have to construct a 99% CI for the difference between the average penetration in the compressed soil and the intermediate soil. To do so, you have to use a t-statistic for two independent samples:

Parámeter of interest: μ₁-μ₂

Interval:

[(X[bar]₁-X[bar]₂)±t_{n_1+n_2-2;1-\alpha/2}*Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }]

t_{n_1+n_2-2;1-\alpha/2}= t_{20+19-2;1-(0.01/2)}= t_{37; 0.995}= 2.715

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{19*0.0196+18*0.0576}{20+19-2} }= 0.195= 0.20

[(2.90-2.29)±2.715*0.20\sqrt{\frac{1}{20} +\frac{1}{19} }]

[0.436; 0.784]

I hope this helps!

5 0
3 years ago
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