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Alexxandr [17]
4 years ago
14

X^2+x+3 factor the polynomial

Mathematics
1 answer:
Zarrin [17]4 years ago
7 0

Answer:

x = -1/2 + (i/2)√11 and x = -1/2 - (i/2)√11

Step-by-step explanation:

This polynomial is a quadratic.  Its coefficients are a = 1, b = 1 and c = 3.

Thus, the discriminant b^2-4ac is 1^2 - 4(1)(3), or 1 - 12, or -11.

Because the discriminant is negative, the roots are complex.

The roots are:

      -1 ±√(-11)        -1 ±i√11

x = --------------- = ----------------, so x = -1/2 + (i/2)√11 and x = -1/2 - (i/2)√11

            2                   2

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3 years ago
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luda_lava [24]

Answer:

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\dfrac{2\sqrt{5} + \sqrt{3}}{2\sqrt{5} - \sqrt{3}} + \dfrac{2\sqrt{5} - \sqrt{3}}{2\sqrt{5} + \sqrt{3}} =

= \dfrac{2\sqrt{5} + \sqrt{3}}{2\sqrt{5} - \sqrt{3}} \times \dfrac{2\sqrt{5} + \sqrt{3}}{2\sqrt{5} + \sqrt{3}} + \dfrac{2\sqrt{5} - \sqrt{3}}{2\sqrt{5} + \sqrt{3}} \times \dfrac{2\sqrt{5} - \sqrt{3}}{2\sqrt{5} - \sqrt{3}}

= \dfrac{23 + 4\sqrt{15}}{17} + \dfrac{23 - 4\sqrt{15}}{17}

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a = \dfrac{46}{17}

b = 0

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