Answer:
a 1
b 6
c 15
Step-by-step explanation:
101% 101/100 = 1 1/100
is 1 complete 100 grid and 1/100 of another grid so you will need 2 grids
589% 589/100 = 5 89/100
is 5 complete 100 grids and 89/100 of another grid so you will need 6 grids
1450% 1450/100 = 14 50/100
is 14 complete grids and 50/100 of another grid so you will need 15 grids
Answer:
$23.50
Step-by-step explanation:
multiply 12 by 1.75 then add 2.50 to it to get the cost of taxi fee of 12 miles
The value of the height of the cylinder is 25cm.
According to the statement
we have to find that the height pf the cylinder with the given value of the volume.
So, For this purpose we know that the
The volume of a cylinder is the density of the cylinder which finds that the amount of material it can carry. Cylinder's volume is given by the formula, πr^2h.
From the given information:
The volume of a cylinder is 225π cubic inches, and the radius of the cylinder is 3 inches.
Then
volume = πr^2h
225π = π3^2h
Now, solve it then
225 = 9h
h = 25.
The value becomes 25.
So, The value of the height of the cylinder is 25cm.
Learn more about volume of a cylinder here
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we have a maximum at t = 0, where the maximum is y = 30.
We have a minimum at t = -1 and t = 1, where the minimum is y = 20.
<h3>
How to find the maximums and minimums?</h3>
These are given by the zeros of the first derivation.
In this case, the function is:
w(t) = 10t^4 - 20t^2 + 30.
The first derivation is:
w'(t) = 4*10t^3 - 2*20t
w'(t) = 40t^3 - 40t
The zeros are:
0 = 40t^3 - 40t
We can rewrite this as:
0 = t*(40t^2 - 40)
So one zero is at t = 0, the other two are given by:
0 = 40t^2 - 40
40/40 = t^2
±√1 = ±1 = t
So we have 3 roots:
t = -1, 0, 1
We can just evaluate the function in these 3 values to see which ones are maximums and minimums.
w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20
w(0) = 10*0^4 - 20*0^2 + 30 = 30
w(1) = 10*(1)^4 - 20*(1)^2 + 30 = 20
So we have a maximum at x = 0, where the maximum is y = 30.
We have a minimum at x = -1 and x = 1, where the minimum is y = 20.
If you want to learn more about maximization, you can read:
brainly.com/question/19819849
The first poster is not an accurate representation of the painting, but the second poster is an accurate representation because the ratio between the first and original lengths did not equal the ratio between the first and original widths but the second poster's ratios were equal.