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anastassius [24]
3 years ago
13

An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 125 amu and 127 amu, with natural abunda

nces of 45% and 55%, respectively. Calculate its average atomic mass. Report your answer to 1 decimal place
Chemistry
1 answer:
mrs_skeptik [129]3 years ago
8 0

Answer:

The average atomic mass is 126.1

Explanation:

To obtain the atomic mass of the isotope we use this formula;

(% composition of isotope 1 * mass number) + (% composition of isotope 2 * mass number)

1. Equate the percentage composition with the mass number of each isotope

45/100 * 125 = 56.25

55/100 * 127 = 69.85

2. Add both answers together you get,

56.25 + 69.85 = 126.1.

The average atomic mass is therefore 126.1

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When the potential difference across a lamp is 3.3V the current is 0.15 calculate the resistance of the lamp and give the unit
marissa [1.9K]

Answer:

22Ω

Explanation:

Given parameters:

Potential difference  = 3.3V

Current  = 0.15A

Unknown:

Resistance  = ?

Solution:

According to ohm's law, potential difference, current and resistance are related by the expression below;

             V = I R

where V is the voltage

           I is the current

          R is the resistance

          3.3 = 0.15 x R

             R = \frac{3.3}{0.15}   = 22Ω

6 0
3 years ago
C12H22O11 is an example of a(n):
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Answer:

molecular compound

Explanation:

it has two or more nonmetal elements and are covalently bonded

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3 years ago
What equation represents the pressure of a gas under ideal conditions?
Leno4ka [110]
P=nRTV
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8 0
4 years ago
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what method can be used to seperate parts of liquid mixture wwhen the entire mixture can pass through a filter
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6 0
4 years ago
Calculate the volume in mL of 0.279 M Ca(OH)2 needed to neutralize 24.5 mL of 0.390 M H3PO4 in a titration.
Vsevolod [243]

The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL

<h3>Balanced equation </h3>

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

  • The mole ratio of the acid, H₃PO₄ (nA) = 2
  • The mole ratio of the base, Ca(OH)₂ (nB) = 3

<h3>How to determine the volume of Ca(OH)₂ </h3>
  • Molarity of acid, H₃PO₄ (Ma) = 0.390 M
  • Volume of acid, H₃PO₄ (Va) = 24.5 mL
  • Molarity of base, Ca(OH)₂ (Mb) = 0.279 M
  • Volume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(0.39 × 24.5) / (0.279 × Vb) = 2/3

9.555 / (0.279 × Vb) = 2/3

Cross multiply

2 × 0.279 × Vb = 9.555 × 3

0.558 × Vb = 28.665

Divide both side by 0.558

Vb = 28.665 / 0.558

Vb = 51.4 mL

Thus, the volume of the Ca(OH)₂ solution needed is 51.4 mL

Learn more about titration:

brainly.com/question/14356286

5 0
2 years ago
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