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Ierofanga [76]
4 years ago
9

PLEASE HELPP!!!!

Chemistry
1 answer:
Natasha_Volkova [10]4 years ago
4 0

Answer:

<em>The combined law is:</em>

          \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}

See the derivation below.

Explanation:

<em><u>1. Boyle's law:</u></em>

    PV=constant\\\\P_1V_1=P_2V_2

<em />

<u><em>2. Charles' law:</em></u>

        \dfrac{V}{T}=constant\\\\\\\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

<em><u>3. Gay-Lussac’s law</u></em>

      \dfrac{P}{T}=constant\\\\\\\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

<u>4. Summary:</u>

  •    PV = K
  •    V/T = K'
  •    P/T = K''

Mulitply PV by V/T and P/T

        PV\times \dfrac{V}{T}\times \dfrac{P}{T}=K\times K'\times K''\\\\\\\dfrac{P^2V^2}{T^2}=constant\\\\\\\sqrt{\dfrac{P^2V^2}{T^2}}=\sqrt{constant}\\\\\\\dfrac{PV}{T}=constant

Thus:

          \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}

Which is<em> the combined law.</em>

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