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zloy xaker [14]
3 years ago
5

Q # # 12 find the volume of the cylinder to the nearest cubic foot Use a calculator

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
8 0
To solve this problem you must apply the formula for calculate the volume of a cylinder, which is shown below: 
 V=πr^2h
 where r is the radius and h is the height of the cylinder
 You have that r is 5 ft and h is 3 ft, therefore:
 V=π(5 ft)^2(3 ft)
 V=236 ft^3

The answer is 236 ft^3
Ronch [10]3 years ago
4 0
The diagram in the question is a cylinder.
;The volume of a cylinder is given by;

Volume = πr²h
;Where π=3.14
             r⇒radius of the base of the cylinder and
             h ⇒ height of the cylinder.

∴Volume = 3.14×5²×3
               =235.5 ft³

To the nearest cubic = 236 ft³

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At a zoo, youth tickets cost $5 and adult tickets cost $9. A group that purchased x youth tickets and y adult tickets spent $90
Marrrta [24]

Answer:

0 ≤ x ≤ 18

Step-by-step explanation:

Let 'x' be the number of youth tickets purchased at the zoo and 'y' be the number of adult tickets purchased at the zoo.

At a zoo, youth tickets cost $5 and adult tickets cost $9. A group spent a total of $90 on tickets. We can write as

5x + 9y = 90

to find x we divide both side by 5

x = (90-9y)/5 =>  90/5 - 9y/5

x = 18 - 9y/5

The domain of the relationship is the possible set of values of x and y that satisfies the equation. The domain of this relationship is

0 ≤ x ≤ 18

At x = 0, it means only adult tickets were purchased.

At x = 18, it means only youth tickets were purchased.

4 0
3 years ago
What is 3(9-3r)= simplifyed
Gwar [14]

27-9r
explaintion:
3•9+3•-3r
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27-9r
6 0
3 years ago
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Solve for x: x-14=39
Jobisdone [24]
Answer is x=53
hope this helps
8 0
3 years ago
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How do you find DE, Round to nearest 10th
Sergeu [11.5K]

Answer:  DE\approx6.0

Step-by-step explanation:

Observe in the figure given in the exercise that four right triangles are formed.

In this case you can use the following Trigonometric Identity to solve this exercise:

cos\alpha=\frac{adjacent}{hypotenuse}

From the figure you can identify that:

\alpha =53\°\\\\hypotenuse=10\\\\adjacent=BE=DE

Then, you can substitute values:

cos(53\°)=\frac{DE}{10}

The next step is to solve for DE in order to find its value. This is:

10*cos(53\°)=DE\\\\DE=6.01

Finally, rounding the result to the nearest tenth, you get that this is:

DE\approx6.0

7 0
3 years ago
Which statement most accurately explains why x^5/x^2 is equal to x^3?
Serggg [28]
\bf \cfrac{x^5}{x^2}\implies \cfrac{x^{3+2}}{x^2}\implies \cfrac{x^3\underline{x^2}}{\underline{x^2}}\implies x^3
8 0
3 years ago
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