Okay, well for a right triangle with legs a and b and hypotenuse c we have:
a2+b2= c2
since we know the hypotenuse (c), we have:
a2+b2= 25
since the short leg is 1 inch shorter than the longer leg,
we can say that a = b-1
So now we have:
(b-1)2+ b2 = 25
b2 - 2b +1 +b2 = 25
2b2-2b -24 = 0
2(b2-b-12) = 0
b2-b-12 = 0
(b-4)(b+3) = 0
Because you can't have a negative length, b = 4
If b = 4, then a = 4-1 = 3
So,
b=4
a=3
True because they are adjacent to each other
Answer:
27) x = 2^(y) – 5.
Asymptote: x = -5.
D: x > -5; (-5, infinity).
R: -infinity < f(x) < infinity; ARN;
(-infinity, infinity).
x → -infinity, f(x) → -infinity.
x → +infinity, f(x) → +infinity.
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28) x = 2^-(y–3).
Asymptote: x = 0.
D: x > 0; (0, infinity).
R: -infinity < f(x) < infinity; ARN;
(-infinity, infinity).
x → -infinity, f(x) → +infinity.
x → +infinity, f(x) → -infinity.
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29) x = 4^(y–2) + 1.
Asymptote: x = 1.
D: x > 1; (1, infinity).
R: -infinity < f(x) < infinity; ARN;
(-infinity, infinity).
x → -infinity, f(x) → -infinity.
x → +infinity, f(x) → +infinity.
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