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3 years ago

Hector recorded the amount of time he spent running for 3 days what is the total number of hours hector spent running

Mathematics

2 answers:

Maslowich3 years ago

7 0

How much did he run for each of those days?

lozanna [386]3 years ago

5 0

Well you have to go by 24x3 and that equals 72 miles

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Final answer

4 0

3 years ago

A caterer makes 15 3/4 quarts of tomato soup. He pours 2 cups of soup into each bowl. How many quarts of soup are in each bowl?

Sindrei [870]

ANSWER:

There are 0.5 quarts in each bowl. There are 31 fully filled bowls. And left over soup is 1 cup of soup.

SOLUTION:

Given, a caterer makes $15 \frac{3}{4}$ which is equal to $\frac{63}{4}$ quarts of tomato soup.

He pours 2 cups of soup into each bowl.

Now let us find how many quarts of soup are in each bowl?

We know that, 1 us liquid quart equals to 4 us cups.

Then, 1 quart = 4 cups

1 cup = $\frac{1}{4}$ quarts

Here, in each bowl caterer pours two cups,

So, 2 cups = $2 \times \frac{1}{4}$ quarts

$= \frac{1}{2} = 0.5 quarts$

Hence, there are 0.5 quarts in each bowl.

Now let us find how many 2-cup bowls of soup can the caterer fill to the top?

From above part, we know that, each bowl has 0.5 quarts.

Then, total bowls with 2- cups of soup = $\frac{\text {total soup}}{\text {soup in one bowl}}$

$=\frac{\frac{63}{4}}{\frac{1}{2}}$

$=\frac{63}{4} \times \frac{2}{1}$$=\frac{63}{2}$$=31.5$$

Here, 0.5 means that a bowl which is not filled to the top. So there are 31 fully filled bowls.

Now, let us find how many cups of soup are left over?

From above part we saw that, there are 31 fully filled bowls but there is a bowl with 0.5 quarts and which is not fully filled.

So, it is the amount of soup which is left over. i.e. 0.5 times of a bowl.

We know that, each bowl will have two cups.

Here left over bowl has half of it filled with soup

So the left over soup is 1 cup of soup.

5 0

3 years ago

Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621

REY [17]

Answer:

The Sum Of The Integers From -6 To 58 is 1690.

Step-by-step explanation:

Given,

$a=-6$

$T_n=58$

We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here $a_1=-6\ and\ a_2=-5$

$\therefore d=a_2-a_1=-5-(-6)=-5+6=1$

Now we use the formula of A.P.

$T_n=a+(n-1)d$

On substituting the values, we get;

$58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65$

So there are 65 terms in between -6 To 58.

That means we have to find the sum of 65 terms in between -6 To 58.

Now we use the formula of Sum of n_terms.

$S_n=\frac{n}{2}(2a-(n-1)d)$

On substituting the values, we get;

$S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690$

Hence The Sum Of The Integers From -6 To 58 is 1690.

5 0

3 years ago

5. A video game console at Games Galore

dmitriy555 [2]

Answer:

$319.60

Step-by-step explanation:

Normal Game console cost : $399.50

Discount: %20 (0.20)

$399.50×0.20= $79.90

Total cost of discount $79.90

$399.50-$79.90= $319.60

New cost after Discount= $319.60

5 0

1 year ago

A) 101* (x+12) B)63* (7x-14) C)(2x+3) (x+41)* Please help :)

IceJOKER [234]

Answer:

A. x+12 = 101

-12 -12

x=89

B. 7x-14 = 63

+14 +14

7x=77

/7 /7

x=11

C. 2x+3 = x+ 41

-x -3 -x -3

x=38

im a god *0*

4 0

2 years ago