Answer:
If the time passed is only 3 months, then it is $2040
Step-by-step explanation:
We can use the quarterly compounded interest equation for this problem: P(1 + r/n)^nt
Step 1: Find out how much 3 months is in a year
<em>In this case, 3/12 which is 1/4</em>
Step 2: Plug in known variables into equation
2000[1 + (0.08)/4)]^[(4)(1/4)]
Step 3: Solve/Plug in calc
You will get $2040
If the time passed in the problem is 1 year, then we can be able to solve how much money he earned per quarter. However, since only 3 months have elapsed, then he has only earned $2040.
If there is 10% of $18 = 18 x 0.9 (1 - 0.1) = $16.20
Therefore the pie costs $16.20
He is saving 18 - 16.20 = $1.80
Answer:
300 students are enrolled.
Step-by-step explanation:
As the university accepts 60% of the students who apply.
As 2000 students apply, it means that:
2000 × 60% ⇒ 2000 × 0.6 = 1200 students are accepted
Out of these 1200, 25% enrolled
1200 × 25% ⇒ 1200 × 0.25 = 300 students are enrolled
Therefore, 300 students are enrolled.
Answer:
It may be Arrow diagram yes or not
Answer:
110 grams
Step-by-step explanation:
CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).
So first finding the mass of 1 molecule of CO2 which is equals to
= mass of 1 carbon atom + masses of 2 oxygen atom, we get
= 12+(16*2)= 12+32= 44 a.m.u.
Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )
1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams
So our answer is 110 grams.
lowkey hope this helped you, good luck whatever you need it for Imaooo
