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vichka [17]
3 years ago
8

Neptune (currently the most distant planet from the Sun!) lies about 4.5x109 kilometers from the Earth. If you were traveling to

ward Neptune at typical highway speeds (about 100 kilometers/hour) how many years would it take to reach Neptune?
Physics
1 answer:
OLEGan [10]3 years ago
3 0

Answer:

5,137 years.

Explanation:

we have a distance and the velocity, so we calculate the time:

time = \frac{distance}{velocity}

the distance is the distance between earth and neptune:

distance = 4.5x10^{9}km

and the velocity is the typical highway speed:

velocity = 100km/h

we divide this quantities:

time = \frac{4.5x10^9km}{100km/h} =4.5x10^7hours

it would take this many hours to get to Neptune at this speed.

Let's convert this to years:

there are 8760 hours in one year:

so the time in years is:

time =\frac{4.5x10^7hours}{8760 hours/year}=5,136.99 years

it would take about 5,137 years.

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Blababa [14]

Answer: c a d b

Explanation:

4 0
3 years ago
Three identical very dense masses of 7500 kg each are placed on the x axis. One mass is at x1 = -100 cm , one is at the origin,
sukhopar [10]

Answer:

0.00354 (N)

Explanation:

Convert to metric system:

x_1 = -100 cm = 1 m

x_2 = 420 cm = 4.2 m

Formula for gravitational force:

F_g = G\frac{mM}{s^2}

where s is the distance between 2 bodies masses m and M

Substitute the number to the formula above and since the 2 forces are acting in opposite direction, the total net gravitational force on the mass of origin be:

F_g = F_{g1} - F_{g2}

F_g = G\frac{m_1M}{x_1^2} - G\frac{m_2M}{x_2^2}

F_g = GM(\frac{m_1}{x_1^2} - \frac{m_2}{x_2^2})

F_g = 6.67*10^{-11} * 7500 (\frac{7500}{1^2} - \frac{7500}{4.2^2})

F_g = 5*10^{-7}(7500 - 425.17)

F_g = 5*10^{-7} * 7074.83

F_g = 0.00354 (N)

5 0
3 years ago
Which of the following does not represent a significant negative environmental impact of using nuclear fuel? a. air pollution b.
sasho [114]
The answer is a. mining.
3 0
3 years ago
The amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C
aniked [119]

The amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C is is 8 times the initial amount of heat.

<h3>What is heat?</h3>

The temperature increment will lead to the increase in the internal energy of the object. This internal energy is the heat.

Given is the change in  temperature ΔT = 7-4 =3°C., diameter D to 2D,

Q = Cp x  ρ(4π/3)D³ x 3..................(1)

and Q' = Cp x  ρ(4π/3)(2D)³ x 3

Q' = Cp x  ρ(4π/3)8D³x 3..................(2)

Dividing both the equation, we have

Q' / Q =8

Q' = 8Q

Thus, the amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C is 8 times the initial amount of heat.

Learn more about heat.

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2 years ago
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