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4 years ago

A ball has a mass of 33.6 grams and a volume of 14.0 cubic centimeters (cc). What is its density?

Physics

2 answers:

viva [34]4 years ago

7 0

Answer:

Density, $d=2.4\ g/cm^3$

Explanation:

Given that,

Mass of the ball, m = 33.6 grams

Volume of the ball, V = 14 cc

Let d is the density of the ball. It can be calculated using the formula as :

$d=\dfrac{m}{V}$

$d=\dfrac{33.6\ g}{14\ cm^3}$

$d=2.4\ g/cm^3$

So, the density of the ball is $2.4\ g/cm^3$ . Hence, this is the required solution.

WINSTONCH [101]4 years ago

5 0

You divide mass by volume in order to get density
33.6/14.0=2.4

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A ball is thrown vertically upward with an initial velocity of 25 m/s. What is its velocity after 3 seconds in the air? (assume

klasskru [66]

Answer:

v = -5 m/s

Explanation:

It is given that,

The initial velocity of the ball, u = 25 m/s

We need to find its velocity after 2 seconds in the air.

Let v is the velocity of the ball after 2 seconds. Using equation of motion to find it.

v = u + at

Here, a = -g

v = u -gt

Putting all the values,

v = 25 - (10)(3)

= 25-30

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So, the velocity of the ball after 3 seconds is 5 m/s and it is in downward direction.

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3 years ago

A balloon has a volume of 3.5-L at 25^ * C . What would be the volume of the balloon if it were placed in a container of hot wat

Romashka-Z-Leto [24]

Answer:

4.3 L

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PV = nRT

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4 years ago

||||| A ball on a porch rolls 60 cm to the porch’s edge, drops 40 cm, continues rolling on the grass, and eventually stops 80 cm

3241004551 [841]

Answer:

$d = 145.6 cm$

Explanation:

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$x_1 = 60 cm$

Then again it will move on horizontal floor

$x_2 = 80 cm$

also in vertical direction it will drop down

$y = 40 cm$

so we have

$x = 60 + 80$

$x = 140 cm$

$y = 40 cm$

so magnitude of net displacement of the ball is given as

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$d = 145.6 cm$

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3 years ago

A particle moves in a velocity field V(x, y) = x2, x + y2 . If it is at position (x, y) = (7, 2) at time t = 3, estimate its loc

MArishka [77]

Answer:

New location at time 3.01 is given by: (7.49, 2.11)

Explanation:

Let's start by understanding what is the particle's velocity (in component form) in that velocity field at time 3:

$V_x=x^2=7^2=49\\V_y=x+y^2=7+2^2=11$

With such velocities in the x direction and in the y-direction respectively, we can find the displacement in x and y at a time 0.01 units later by using the formula:

$distance=v\,*\, t$

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Therefore, adding these displacements in component form to the original particle's position, we get:

New position: (7 + 0.49, 2 + 0.11) = (7.49, 2.11)

6 0

3 years ago

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Shalnov [3]

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For example, the "S" in "SO" stands for "Extra Hard Service and the "O" stands for oil resistant.

Read more about Cords here brainly.com/question/13600515

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3 years ago