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4 years ago

The answer to this and why

Chemistry

1 answer:

adoni [48]4 years ago

7 0

Answer : D
Why ? : Because dissolved minerals would be a liquid and later solidifies into a crystal which would be in phase of being a solid

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Predict which surface will melt ice faster. Wood or metal? Why?

Kay [80]

Answer:

Explanation:

Some materials allow heat to pass through easily, while others do not. Even though the metal block feels colder than the wooden block, it transfers the heat it has to the ice cube more easily than the wooden block does, and this makes the ice cube melt faster.

8 0

4 years ago

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The specific rate constant, k, for radioactive beryllium–11 is 0.049 s–1. What mass of a 0.500 mg sample of beryllium–11 remains

Sonja [21]

Answer: The mass of sample that remained is 0.127 mg

Explanation:

The integrated rate law equation for first-order kinetics:

$k=\frac{2.303}{t}\log \frac{a}{a-x}$ ......(1)

Given values:

a = initial concentration of reactant = 0.500 mg

a - x = concentration of reactant left after time 't' = ?mg

t = time period = 28 s

k = rate constant = $0.049s^{-1}$

Putting values in equation 1:

$0.049s^{-1}=\frac{2.303}{28s}\log (\frac{0.500}{(a-x)})\\\\\log (\frac{0.500}{(a-x)})=\frac{0.049\times 28}{2.303}\\\\\frac{0.500}{a-x}=10^{0.5957}\\\\frac{0.500}{a-x}=3.94\\\\a-x=\frac{0.500}{3.942}=0.127mg$

Hence, the mass of sample that remained is 0.127 mg

5 0

3 years ago

Consider the fructose-1,6-bisphosphatase reaction. Calculate the free energy change if the ratio of the concentrations of the pr

Lyrx [107]

Answer:

The free energy change for the reaction at 37.0°C is -8.741 kJ.

Explanation:

The free energy of the reaction is given by :

$\Delta G=\Delta G^o+RT\ln K$

where,

$\Delta G^o$ = standard Gibbs free energy

R = Gas constant = $8.314J/K mol$

T = temperature in Kelvins

K = equilibrium constant

We have :

$\Delta G^o=-16.7 kJ/mol=-16,700 J/mol$

1 kJ = 1000 J

T = 37.0 C = 37 +273.15 K = 310.15 K

Ratio of concentrations of the products to the concentrations of the reactants =K = 21.9

$\Delta G=-16,700 J/mol+8.314J/K mol\times 310.15 K \ln[21.9]$

$=-8,741.22 J = -8.741 kJ$

The free energy change for the reaction at 37.0°C is -8.741 kJ.

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3 years ago

Calculate the work done when a force of 4 N pulls a box along the floor for a distance of 0.3 m.

Yuki888 [10]

Answer:

<h2>1.2 Joule</h2>

solution,

Force=4 N

Distance=0.3 m

Now,

 $work = f \times d \\ \: \: \: \: \: \: \: \: \: \: \: = 4 \times 0.3 \\ \: \: \: \: \: \: \: \: \: \: \: = 1.2 \: joule$ 

hope this helps...

Good luck on your assignment....

8 0

4 years ago

gold has a density of 19.32 g/cm3 if you cut a piece of gold in half how much will the density of each piece be?

Rashid [163]

Answer:

19.32 g/cm³

Explanation:

The density will remain the same no matter how many times you cut the gold. The density is g/cm³ or g/mL. Density is essentially how many grams 1 mL of a compound weighs.

7 0

3 years ago

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