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Oksi-84 [34.3K]
3 years ago
6

Which method is the most efficient method to use to solve x^2+4x+3=0

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
3 0

Answer:

Factoring

Step-by-step explanation:

To solve the equation x ^ 2 + 4x + 3 = 0, you must apply the factoring method.

You must find two real numbers b and c such that:

b + c = 4

and

b(c) = 3

Then the expression:

x ^ 2 + 4x + 3 = 0 = (x + b)(x + c)

You can prove that:

b = 3\\c = 1

So

x ^ 2 + 4x + 3 = 0 = (x + 3)(x + 1)

(x + 3)(x + 1) = 0

x +3 = 0 or x + 1 = 0

x = -3 or x = -1

AlekseyPX3 years ago
3 0

X will be -1 and -3!

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What is the equation of the line that is parallel to the line y - 1 =4(x+3)? no links.
Misha Larkins [42]

Answer:

4th option

Step-by-step explanation:

The slope m = 4

b = 32-(4×4) = 16

y = mx+b

or, y = 4x+16

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3 years ago
What would the answer to this question be? show work please
AURORKA [14]

Answer:

B

Step-by-step explanation:

The volume of a rectangular prism is the length times width times height.

V = LWH

V = (4√3)(3√6)W

V = 12√18 W

V = 36√2 W

If the volume is irrational, then W cannot have a radical that is half of a perfect square, because when multiplied by √2, that would yield a rational volume.  For example, √18 × √2 = √36 = 6.

Therefore, the answer must be B, because 12 is not half of a perfect square.

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5 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%28%20%7Bx%7D%5E%7B2%7D%20%20%2B%7B3x%7D%5E%7B2%7D%20%20-%202%29" id="TexFormula1" title="3(
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Point Fis on line segment EG. EG = 100, EF = 4x - 20, and FG = 2x + 30. Write an equation that you would use to solve for x, the
andrew-mc [135]

Step-by-step explanation:

Line segment = EG

point on a line segment = F

EG = 100

EF = 4x - 20

FG = 2x + 30

a/q, EF + FG = EG

the equation is

4x - 20 + 2x + 30 = 100

now solution for x is

→ 4x - 20 + 2x + 30 = 100

→ 6x + 10 = 100

→ 6x = 100 - 10 = 90

→ x = 90/6 = 15

therefore, value of x is 15.

and according to given information

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FG = 2x + 30 = 2(15) + 30 = 30 + 30 = 60

hope this answer helps you dear..take care and may u have a great day ahead!

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