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dem82 [27]
3 years ago
11

HELP ME ASAP!!!

Mathematics
1 answer:
frozen [14]3 years ago
5 0
Find a common denominator which woukd be 6. imagine he divided the pie ibto 6 slices and he ate 1/2 of the pie so there are 3 slices left. after dinner he ate a third of what was left so he ate 1 slice. 1 slice out of 6 slices is 1/6
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2+3i divided by 3-3i ( a+bi form)
Oduvanchick [21]
(2+3i):(3-3i)=\frac{2+3i}{3-3i}\cdot\frac{3+3i}{3+3i}=\frac{(2+3i)(3+3i)}{(3-3i)(3+3i)}=\frac{6+6i+9i-9}{3^2-(3i)^2}=\frac{-3+15i}{9+9}\\\\=\frac{-3+15i}{18}=-\frac{3}{18}+\frac{15i}{18}=-\frac{1}{6}+\frac{5}{6}i
6 0
3 years ago
What percent of 126 is 22
Anna11 [10]
In order to solve, set up a proportion: 22/126=x/100. Cross multiply: 2200=126x. Divide by 126 on both sides: 17.46%=x
8 0
3 years ago
All questions to be solved using linear combination.
monitta
1)
I:x-y=-7
II:x+y=7

add both equations together to eliminate y:
x-y+(x+y)=-7+7
2x=0
x=0

insert x=0 into II:
0+y=7
y=7

the solution is (0,7)

2)
I: 3x+y=4
II: 2x+y=5

add I+(-1*II) together to eliminate y:
3x+y+(-2x-y)=4+(-5)
x=-1

insert x=-1 into I:
3*-1+y=4
y=7

the solution is (-1,7)

3)

I: 2e-3f=-9
II: e+3f=18

add both equations together to eliminate f:
2e-3f+(e+3f)=-9+18
3e=9
e=3

insert e=3 into I:
2*3-3f=-9
-3f=-9-6
-3f=-15
3f=15
f=5

the solution is (3,5)

4)
I: 3d-e=7
II: d+e=5

add both equations together to eliminate e:
3d-e+(d+e)=7+5
4d=12
d=3

insert d=3 into II:
3+e=5
e=2

the solution is (3,2)

5)
I: 8x+y=14
II: 3x+y=4

add I+(-1*II) together to eliminate y
8x+y+(-3x-y)=14-4
5x=10
x=2

insert x=2 into II:
3*2+y=4
y=4-6
y=-2

the solution is (2,-2)
8 0
3 years ago
What expression is equivalent to y•y•y•z•z•z•z
Stolb23 [73]

Answer:

y^3 * z^4

Step-by-step explanation:

y*y*y = y^3

z*z*z*z = z^4

8 0
3 years ago
Read 2 more answers
How to solve this problem 75-5(2x6)
alexandr1967 [171]
First do 75-5 then multypliy 2.6
=62
5 0
4 years ago
Read 2 more answers
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