robert wants to build a fence in his back yard that is 28 feet by 26 feet. how much fence would he need

Find the value of x to the nearest tenth. tan 34° = 20

Likurg_2 [28]

Answer:

The value of x = 13.5.

Step-by-step explanation:

In this question x is missing.

So, the question would be:

tan 34° = x/20.

Now, to find the value of $x$ :

$tan 34 = \frac{x}{20}$

$\frac{x}{20} = tan 34$

Multiplying both sides by 20 we get:

$x=tan 34\times 20$

On simplifying both sides we get:

$x=13.49$

So, to get the value of $x=13.49$ to nearest tenth is 13.5. As we see in hundredth place it is 9 and 4 in tenth place, so after rounding to tenth place 4 will change to 5 so the value is 13.5.

Therefore, the value of x = 13.5.

7 0

3 years ago

D(1) = 1. d(n) = n.d(n-1), for n > 2

melamori03 [73]

Answer:

Step-by-step explanation:

You are stupid

8 0

3 years ago

Read 2 more answers

Jason volunteered at the pet shelter twice as many times as keith. Noah volunteered three times more often than jason. Keith vol

Alchen [17]

Answer:

$y = 6\cdot z$

$y$ - Number of times that Noah volunteered at pet shelter.

$z$ - Number of times that Keith volunteered at pet shelter.

Step-by-step explanation:

After reading the statement of the problem, the following variables are described below:

$x$ - Number of times that Jason volunteered at pet shelter.

$y$ - Number of times that Noah volunteered at pet shelter.

$z$ - Number of times that Keith volunteered at pet shelter.

The following two relations are presented herein:

Noah and Jason

$y = 3\cdot x$

Jason and Keith

$x = 2\cdot z$

The relationship between the number of times Noah and Keith volunteered is:

$y = 6\cdot z$

7 0

3 years ago

Derivative of tan(2x+3) using first principle

kodGreya [7K]

$f(x)=\tan(2x+3)$

The derivative is given by the limit

$f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h$

You have

$\displaystyle\lim_{h\to0}\frac{\tan(2(x+h)+3)-\tan(2x+3)}h$
$\displaystyle\lim_{h\to0}\frac{\tan((2x+3)+2h)-\tan(2x+3)}h$

Use the angle sum identity for tangent. I don't remember it off the top of my head, but I do remember the ones for (co)sine.

$\tan(a+b)=\dfrac{\sin(a+b)}{\cos(a+b)}=\dfrac{\sin a\cos b+\cos a\sin b}{\cos a\cos b-\sin a\sin b}=\dfrac{\tan a+\tan b}{1-\tan a\tan b}$

By this identity, you have

$\tan((2x+3)+2h)=\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}$

So in the limit you get

$\displaystyle\lim_{h\to0}\frac{\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}-\tan(2x+3)}h$
$\displaystyle\lim_{h\to0}\frac{\tan(2x+3)+\tan2h-\tan(2x+3)(1-\tan(2x+3)\tan2h)}{h(1-\tan(2x+3)\tan2h)}$
$\displaystyle\lim_{h\to0}\frac{\tan2h+\tan^2(2x+3)\tan2h}{h(1-\tan(2x+3)\tan2h)}$
$\displaystyle\lim_{h\to0}\frac{\tan2h}h\times\lim_{h\to0}\frac{1+\tan^2(2x+3)}{1-\tan(2x+3)\tan2h}$
$\displaystyle\frac12\lim_{h\to0}\frac1{\cos2h}\times\lim_{h\to0}\frac{\sin2h}{2h}\times\lim_{h\to0}\frac{\sec^2(2x+3)}{1-\tan(2x+3)\tan2h}$

The first two limits are both 1, and the single term in the last limit approaches 0 as $h\to0$ , so you're left with

$f'(x)=\dfrac12\sec^2(2x+3)$

which agrees with the result you get from applying the chain rule.

7 0

3 years ago

A farmer has 500 acres to plant acres of corn, x, and acres of cotton, y. Corn costs $215 per acre to produce, and cotton costs

hodyreva [135]

Answer:

x + y = 500

215x + 615y = 187,500

Step-by-step explanation:

The first equation can show the amount of land. The farmer has 500 acres to plant corn, x, and cotton, y.

x + y = 500

The second equation can show the cost. The farmer has $187,500 to invest when corn costs $215 per acre and cotton costs $615 per acre.

215x + 615y = 187,500

The system of equations is

x + y = 500

215x + 615y = 187,500

4 0

3 years ago