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2 years ago

robert wants to build a fence in his back yard that is 28 feet by 26 feet. how much fence would he need

Mathematics

1 answer:

il63 [147K]2 years ago

4 0

He would need 728 ft of fence in order to build a fence. 28 x 26 would equal 728.

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A manager records the repair cost for 4 randomly selected stereos. A sample mean of $82.64 and standard deviation of $14.32 are

zysi [14]

Answer:

CI = (70.861 , 94.418)

Step-by-step explanation:

In order to determine the 90% confidence interval you use the following formula (for a population approximately normal):

$CI=(\overline{x}-Z_{\alpha/2}\frac{\sigma}{\sqrt{n}},\overline{x}+Z_{\alpha/2}\frac{\sigma}{\sqrt{n}})$ (1)

$\overline{x}$ : mean = 82.64

σ: standard deviation = 14.32

n: sample = 4

α: tail area = 1 - 0.9 = 0.1

Z_α/2 = Z_0.05: Z factor = 1.645

You replace these values and you obtain:

$Z_{0.05}(\frac{14.32}{\sqrt{4}})=(1.645)(\frac{14.32}{\sqrt{4}})=11.778$

The confidence interval will be:

$CI=(82.64-11.778,82.64+11.778)=(70.861,94.418)$

The 90% confidence interval is (70.861 , 94.418)

6 0

3 years ago

HELP PLZ PLZ PLZ!!! Maths

TiliK225 [7]

these inequalities can be solved just like equations

a. x - 7 > 25

+ 7 +7 x > 32the number line would have a filled in circle at 32 with an arrow pointing to the rightb. x - 8 < 5+8 +8x < 13 the number line would have an empty circle at 13 with an arrow pointing to the leftc.x + 11 > 23 - 11 - 11x > 12the number line would have an empty circle at 12 with an arrow pointing to the rightd. x + 12 < 6 - 12 - 12 x < -6the number line would have a filled in circle at -6 with an arrow pointing to the lefta. 21 < x + 18 -18 -18 3 < xx > 3b. 16 < x - 7 + 7 + 7 23 < x x > 23c. 12 > x - 7 + 7 + 7 19 > x x < 19d. 29 < x + 53 - 53 - 53 -24 < x x > -24e. 15 > x + 19 -19 -19 -4 > x x < -4f. 35 > x - 8 +8 +8 43 > x x < 43g. -6 < x - 18 +18 +18 12 < x x > 12h. -15 < x - 2 + 2 +2 -13 < x x > -13

3 0

3 years ago

Find the principal square root of 14.

Anika [276]

Sqrt14 = 3.74 (2dp)

The principal root is always the positive.

5 0

2 years ago

An oval track is made by erecting semicircles on each end of a 60m by 120m rectangle. Find the length of the track and the area

vodomira [7]

Refer to the figure shown below.

Because the question states that the semi circles are at the ends of the rectangle, each semicircle has a radius of 30 m.

The circumference of the oval is
2π(30) + 2*120 = 60π + 240 m = 428.5 m

The area of the oval is
π(30²) + 60*120 = 900π + 7200 m² = 1.0027 x 10⁴ m²

Note:
If the semi circles are placed on the 120-m sides of the rectangle, then similar calculations yield:
Circumference = 120π + 120 m = 497 m
Area = 3600π + 7200 m² = 1.851 x 10⁴ m²

Answer:
If the semi circles are placed on the 60-m sides of the rectangle, then
Circumference = 60π + 240 m, or 428.5 m
Area = 900π + 7200 m², or 1.0027 x 10⁴ m²

if the semi circles are placed on the 120-m sides of the rectangle, then
Circumference = 120π + 120 m, or 497 m
Area = 3600π + 7500 m², or 1.851 x 10⁴ m²

3 0

3 years ago

One side of the triangle is 8 in, and the other two sides are equal to a positive whole number of inches. What is the smallest p

frutty [35]

In a triangle the sum of two sides is always greater than the third side.

If one side = 8 in and other two sides are equal to a positive whole number, then the smallest possible sum of the other two sides = 9 in ⇒
<span>Smallest possible perimeter = 8 + 9 = 17 in</span>

6 0

2 years ago