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2 years ago

How can models be used to generate and analyze patterns?

2 answers:

5 0

Models are used for people to visualize whats happening and how it works instead of using just plain numbers if were talking in terms of math.

Lilit [14]2 years ago

4 0

Models can be used to describe, extend, and make generalizations about certain mathematical situations.

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PLEASE HELP ME

kvasek [131]

Answer:

Step-by-step explanation:

The binomial coefficient is calculated as:

$nCx=\frac{n!}{x!(n-x)!}$

It means that there are nCx ways to select x elements from a group of n elements.

So, If the researcher wants to determine the probability that 6 out of the next 8 individuals in his community are in favor of the president, we can replace n by 8 and x by 6 and calculated the binomial coefficient as:

$8C6=\frac{8!}{6!(8-6)!}=28$

5 0

2 years ago

Given then function f(x) =3(x+2)-4 solve for the inverse function when x=2

Alisiya [41]

F(x) (or y)=8

PEMDAS helps

7 0

3 years ago

Read 2 more answers

Find a 12% tip on a check for $40.

pickupchik [31]

Answer:

Step-by-step explanation:

40(12/100)

480/100

$4.80

3 0

2 years ago

Read 2 more answers

I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu

ra1l [238]

The imaginary unit $i$ belongs to the set of complex numbers, denoted by $\mathbb C$ . These numbers take the form $a+bi$ , where $a,b$ are any real numbers.

The set of real numbers, $\mathbb R$ , is a subset of $\mathbb C$ , where each number in $\mathbb R$ can be obtained by taking $b=0$ and letting $a$ be any real number.

But any number in $\mathbb C$ with non-zero imaginary part is not a real number. This includes $i$ .

"is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because $2=2+0i$ .

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising $i$ to the $i$ -th power. Since $i=e^{i\pi/2}$ , we have

$i^i=\left(e^{i\pi/2}\right)^i=e^{i^2\pi/2}=e^{-\pi/2}\approx0.2079$

3 0

2 years ago

Type the correct answer in each box.

nataly862011 [7]

Answer:

i dont knwo

Step-by-step explanation:

5 0

2 years ago