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aleksandrvk [35]
3 years ago
6

Plzzzzzz helppppp asappppp ****will mark brainliest ****

Mathematics
1 answer:
Oxana [17]3 years ago
4 0

The triangle with legs x and y is a 30 - 60 - 90 triangle. The patterns of the legs are as follows:

short leg (opposite 30 degree angle) = 1 unit

long leg (opposite 60 degree angle) √3 units

hypotenuse = 2 units.

The pattern is that we double the short leg to get the hypotenuse, or, we go in reverse and take half the hypotenuse to get the short leg.

In the picture we are told the hypotenuse is 16. That makes the short leg as 8, which is x in the picture.

Now we find the long leg and multiply it by √3. This gives us 8√3., the side y.

Thus, x = 8 and y = 8√3.

You might be interested in
Rosa has $117 in her savings account and $95 in her checking account. Each week she will put $21 into her savings account and $2
mr_godi [17]

Answer:

It will take Rosa 5 and a half (5.5) weeks to have the same amount of money in both accounts.

Step-by-step explanation:

For this problem, we will have to set two expressions equal to each other. The first expression will represent Rosa's saving account, which already has $117 in it. Every week (x), she adds $21 to her savings account:

21x+117

The second expression will represent Rosa's checking account. Rosa's checking account already has $95 in it. Every week (x), she adds $25 to her checking account:

25x+95

Now that we have our two expressions, set them equal to each other. This is our equation that will be used to find the number of weeks (x) it takes until Rosha has the same amount of money in both accounts:

21x+117=25x+95

Subtract 21x from both sides of the equation:

117=4x+95

Subtract 95 from both sides of the equation:

22=4x

Divide both sides of the equation by the coefficient of x, which is 4:

5.5=x

x=5.5

So it will take five and a half weeks for her accounts to have the same amount of money.

_

Check your work by substituting 5.5 into the initial equation:

21(5.5)+117=25(5.5)+95

115.5+117=137.5+95

232.5=232.5

Since the accounts have the same amount, the answer is correct!

6 0
3 years ago
Read 2 more answers
A vertical pole is supported by two ropes staked to the ground on opposite sides of the pole. One rope is 8 meters long, and the
aniked [119]
Establish two right triangles, both with the height of the pole, h.

Call x the distance from the pole to one stake. Then the distance from the other stake to the pole is 6 -x.

Apply Pytagora's equation to both triangles.

1) h^2 = 7^2 - x^2

2) h^2 = 8^2 - (6-x)^2

Eaual 1 to 2

7^2 - x^2 = 8^2 - 6^2 +12x -x^2

12x = 7^2 -8^2 +6^2 = 49 -64 + 36 = 21

x = 1.75

Substitue x-value in 1

h^2 = 49 - (1.75)^2 = 45.94

h = sqrt(45.94) = 6.78

Answer: option d.
8 0
2 years ago
Read 2 more answers
Which function has a phase shift of pi/2 to the right?
Bess [88]
If it helps you any

\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\
\end{array}

\bf \begin{array}{llll}

\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}

so.. check coefficients C and B for the horizontal shift
7 0
3 years ago
Read 2 more answers
Unscramble each of the clue words.
ella [17]
The first is two step
Second property
Third addition
Fourth division
Fifth variable
And the last is multiplication
Sorry I don’t know the rest
8 0
3 years ago
For question 12, use the graph to guess one zero for the polynomial whose graph is shown. Then, factor completely.
SVEN [57.7K]

Answer:

x³ - 6·x² + 6·x + 8 = (x - 4) × (x - (1 + √3)) × (x + 1 + √3)

Step-by-step explanation:

From the given graph of the polynomial, x³ - 6·x² + 6·x + 8, we have that one of the zeros of the polynomial, which is one point the graph cuts the x-axis is given as follows;

At a zero, we have, x = 4

∴ x - 4 = 0 is a factor of the polynomial

Dividing the given polynomial by (x - 4), gives;

<u>x² - 2·x - 2</u>

(x³ - 6·x² + 6·x + 8)÷(x - 4)

<u>x³ -4·x²</u>

-2·x² + 6·x + 8

<u>-2·x² + 8·x</u>

-2·x + 8

<u>-2·x + 8</u>

<u>0</u>

∴ (x³ - 6·x² + 6·x + 8)÷(x - 4) = x² - 2·x - 2

∴ (x - 4) × (x² - 2·x - 2) = x³ - 6·x² + 6·x + 8

Factorizing x² - 2·x - 2, gives;

x = (2 ± √((-2)² - 4×1×(-2)))/(2 × 1) =  (2 ± 2·√(3)/(2) = (1 ± √(3)

Therefore, x = 1 + √3, (x - (1 + √3)) = 0 or x = 1 - √3, (x - (1 - √3)) = 0 which gives the factors, after factorizing completely as follows;

x³ - 6·x² + 6·x + 8 = (x - 4) × (x - (1 + √3)) × (x + 1 + √3)

4 0
3 years ago
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