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liberstina [14]
3 years ago
11

Factor as the product of two binomials. x^2 + 3x +2

Mathematics
1 answer:
Sergio039 [100]3 years ago
5 0
The answer would be (x+2) (x+1)
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Please help me with this. Please!
jonny [76]

Answer:

214

Step-by-step explanation:

A circle is 360 degrees

Arc EF is 146 degrees

EF + EDF = full circle

146 + EDF = 360

Subtract 146 from each side

146-146 +EDF = 360-146

EDF =214

4 0
3 years ago
Find the equation of a sphere if one of its diameters has endpoints: (-9, -12, -6) and (11, 8, 14).
baherus [9]

Answer:

Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is (x-1)^{2}+(y+2)^{2}+(z-4)^{2} = 30.

Step-by-step explanation:

There are two kew parameters for a sphere: Center (h, k, s) and Radius (r). The radius is the midpoint of the line segment between endpoints. That is:

C(x,y,z) = \left(\frac{-9+11}{2},\frac{-12+8}{2},\frac{-6+14}{2}   \right)

C(x,y,z) = (1,-2,4)

The radius can be found by halving the length of diameter, which can be determined by knowning location of endpoints and using Pythagorean Theorem:

r = \frac{1}{2}\cdot \sqrt{(-9-11)^{2}+(-12-8)^{2}+(-6-14)^{2}}

r = 10\sqrt{3}

The general formula of a sphere centered at (h, k, s) and with a radius r is:

(x-h)^{2}+(y-k)^{2}+(z-s)^{2} = r^{2}

Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is (x-1)^{2}+(y+2)^{2}+(z-4)^{2} = 30.

8 0
3 years ago
If IN= 2x + 10 and AT=26, find the value of x.
Lunna [17]

Answer: A

Step-by-step explanation:

Substitute x for 8.

2(8)+10

16+10=26

4 0
3 years ago
All states require auto insurance.<br><br> True <br><br> False
postnew [5]

Answer:

true

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
I need some help pleaseee
Anastasy [175]
The answer is 381.7 m^3
4 0
3 years ago
Read 2 more answers
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