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otez555 [7]
2 years ago
6

Solve the equation: 3^3x-8=81 PLZ HELPPPP

Mathematics
1 answer:
pentagon [3]2 years ago
8 0

Answer:

if you are solving for then it is x = 4/3

Step-by-step explanation:

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Find the slope of the line
natta225 [31]

Answer:

slope = - 1

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 1, 4) and (x₂, y₂ ) = (2, 1)

m = \frac{1-4}{2+1} = \frac{-3}{3} = - 1

4 0
3 years ago
Read 2 more answers
Your teacher is choosing 2 students to run an errand for her. There are 12 girls and 10 boys in the class. What is the probabili
Ne4ueva [31]

Answer:

2/7

Step-by-step explanation:

There are 22 (12 + 10) total students in the class. That means that the chance of the first student picked being a girl is 12/22.

Now, we must calculate the chance of the next student to be picked <em>also </em>being a girl - however, there is a trap here! Remember that since a girl has been picked, the total student pool has decreased to 21 and and the total number of girls has decreased to 11. This means the new chance of girl being picked is 11/21.

To find the probability of both these events happening in conjunction, these fractions must be multiplied. 12/22 * 11/21 = 132/462, which simplifies to 2/7.

4 0
2 years ago
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Can someone help me with this math homework please!
jolli1 [7]

Answer:

(-3,-6) and (-3,2)

Step-by-step explanation:

A line with an undefined slope is vertical. In this case it must have x coordinates equal to -3

4 0
3 years ago
Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a
Bond [772]

f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x

f has critical points where f'=0:

3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi

where n is any integer. We get solutions in the interval \left[0,\frac\pi3\right] for n=0, for which x=\frac\pi4.

At this critical point, we have f\left(\frac\pi4\right)=3\sqrt2\approx4.243.

At the endpoints of the given interval, we have f(0)=3 and f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098.

So we have the extreme values

\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2

\min\limits_{x\in\left[0,\frac\pi3\right]}f=3

8 0
3 years ago
IDK this I really need help with this if anyone wants to help plz do
LUCKY_DIMON [66]
(b+5)(b-7)
hope it can help u
5 0
3 years ago
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