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3 years ago

Make a Graph Ms. McGill has 8 containers of liquid in her refrigerator. Three of the containers hold a pint. 38 of

Mathematics

1 answer:

timurjin [86]3 years ago

7 0

Idk do u know it827374

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Graph the system of equations. {x−y=64x+y=4

Fantom [35]

X-y=6 Equation 1
x+y=4 Equation 2

To graph the given system of equation, first find x and y-intercept of each equation.
x-y=6
When y=0
x=6 Point is (6,0)
When x=0
-y=6
y=-6 Point is (0,-6)

Now x-intercept and y-intercept for equation 2.
x+y=4
When x=0
y=4 Point is (0,4)
When y=0
x=4 Point is (4,0)

Now plot these points on the graph, the lines intersect each other at point (5,-1), which is the solution of the given system.

Answer: (5,-1)

5 0

3 years ago

Explain your answer !!<br><br> Have a great day <br><br> Will give brainlst

Elina [12.6K]

Answer:

columbia- 1

vene-2

brazil- 3

peru- 4

Step-by-step explanation:

3 0

3 years ago

Subtract the cube root of the product of x and 3y from the square of the sum of a and b.

rosijanka [135]

Answer:

a^2 + b^2 + 2ab - (3xy)^1/3

Step-by-step explanation:

Here we want to make a subtraction

Cube root of the product of x and 3y

x * 3y = 3xy

Cube root of this;

(3xy)^1/3

The sum of a and b is (a + b)

Square of this sum;

(a + b)^2 = a^2 + 2ab + b^2

Now, subtract the cube root

we have;

a^2 + b^2 + 2ab - (3xy)^1/3

7 0

2 years ago

10^x • 100^2x = 1000^5. Step by Step

nordsb [41]

Step one: set the base of each term to be the same (10)
(10ˣ)(10²)²ˣ = (10³)⁵
(10ˣ) (10⁴ˣ)= (10¹⁵)
10⁵ˣ = 10¹⁵
Because the indices are the same we can equate the two.
5x = 15
x = 3

Check 10⁵ˣ³ = 10¹⁵ 10¹⁵=10¹⁵

4 0

3 years ago

Please help!

777dan777 [17]

Answer:

$\begin{array}{ccc}\text{Radius}&\text{Volume of sphere}&\text{Volume of cylinder}\\&&\\1&\dfrac{4}{3}\pi &2\pi \\&&\\2&\dfrac{32}{3}\pi &16\pi \\&&\\3&36\pi &54\pi \\&&\\4&\dfrac{256}{3}\pi &128\pi \\&&\\5&\dfrac{500}{3}\pi &250\pi\end{array}$

Step-by-step explanation:

Use formulas for the volumes:

$V_{sphere}=\dfrac{4}{3}\pi r^3,\\ \\V_{cylinder}=\pi r^2h=\pi r^2\cdot 2r=2\pi r^3.$

1. When r=1,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 1^3=\dfrac{4}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 1^3=2\pi.$

2. When r=2,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 2^3=\dfrac{32}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 2^3=16\pi.$

3. When r=3,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 3^3=36\pi,\\ \\V_{cylinder}=2\pi \cdot 3^3=54\pi.$

4. When r=4,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 4^3=\dfrac{256}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 4^3=128\pi.$

5. When r=5,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 5^3=\dfrac{500}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 5^3=250\pi.$

Note that for all r,

$\dfrac{V_{sphere}}{V_{cylinder}}=\dfrac{\frac{4}{3}\pi r^3}{2\pi r^3}=\dfrac{2}{3}.$

8 0

3 years ago

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